Reputation: 4596
Consider the following code snippet. It flags a syntax error at the break statement.
digits = list(str(102))
dummy = list(str(102/2))
for j in digits:
dummy.remove(j) if j in dummy else break
How do I fix this?(I want to still use the ternary operator)
Upvotes: 7
Views: 5724
Reputation: 180411
You cannot use break in Your loop logic can be re written using itertools.takewhile if you want a more succinct solution
digits = list(str(102))
dummy = list(str(102/2))
from itertools import takewhile
for d in takewhile(dummy.__contains__, digits):
dummy.remove(d)
You can also remove the need for the else using a for loop by reversing your logic, check if j is not in dummy breaking when that is True:
for j in digits:
if j not in dummy:
break
dummy.remove(j)
Also if you want to remove all occurrences of any of the initial elements from digits that are in dummy, remove won't do that for any repeating elements but using a list comp after creating a set of elements to remove will:
digits = str(102)
dummy = list(str(102/2))
st = set(takewhile(dummy.__contains__, digits))
dummy[:] = [d for d in dummy if d not in st]
print(dummy)
You can also iterate over a string so no need to call list on digits unless you plan on doing some list operations with it after.
Upvotes: 3
Reputation: 30813
Edit:
(see my conversation with Stefan Pochmann in the comments)
Ternary operator is not for only statement, but rather for assignment or for expression (and break
is an only statement):
a = 5 if cond else 3 #OK
do() if cond else dont() #also OK
do() if cond else break #not OK
use normal if-else
statement to do statements:
if cond:
do()
else:
break
Upvotes: 6