Reputation: 273125
I want to turn this:
let x = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
into this:
[1, 2, 3, 4, 5, 6, 7, 8, 9]
very gracefully.
The most straightforward way, of course, is
var y = [Int]()
x.forEach { y.appendContentsOf($0) }
But that makes the resulting array mutable, which is unnecessary. I don't like this way.
I tried using reduce
:
let y = x.reduce([Int]()) { (array, ints) -> [Int] in
array.appendContentsOf(ints)
return array
}
But the compiler complains that array
is immutable, so I can't call the mutating method appendContentsOf
.
Hence, I added some stuff:
let y = x.reduce([Int]()) { (array, ints) -> [Int] in
var newArr = array
newArr.appendContentsOf(ints)
return newArr
}
This is just plain bad. I have an instinct that this is not swifty.
How can I flatten an array more swiftily than the above methods? A one-liner would be good.
Upvotes: 17
Views: 9839
Reputation: 500
You only need to use 2 function to do that
joined()
compactMap
let y = x.compactMap{$0}.joined().compactMap{$0}
Reference for more about FlattenSequence
Upvotes: 1
Reputation: 118741
There's a built-in function for this called joined
:
[[1, 2, 3], [4, 5, 6], [7, 8, 9]].joined()
(Note that this doesn't actually return another Array, it returns a FlattenSequence
, but that usually doesn't matter because it's still a sequence that you can use with for
loops and whatnot. If you really care, you can use Array(arrayOfArrays.joined())
.)
The flatMap
function can also help you out. Its signature is, roughly,
flatMap<S: SequenceType>(fn: (Generator.Element) -> S) -> [S.Generator.Element]
This means that you can pass a fn
which for any element returns a sequence, and it'll combine/concatenate those sequences.
Since your array's elements are themselves sequences, you can use a function which just returns the element itself ({ x in return x }
or equivalently just {$0}
):
[[1, 2, 3], [4, 5, 6], [7, 8, 9]].flatMap{ $0 }
Upvotes: 29
Reputation: 92549
With Swift 5, you can choose one of the three following ways in order to flatten an array.
Array
's flatMap(_:)
methodWith Swift, types that conform to Sequence
protocol (including Array
) have a flatMap(_:)
method. Array
's flatMap(_:)
has the following declaration:
func flatMap<SegmentOfResult>(_ transform: (Element) throws -> SegmentOfResult) rethrows -> [SegmentOfResult.Element] where SegmentOfResult : Sequence
Returns an array containing the concatenated results of calling the given transformation with each element of this sequence.
The Playground sample code below shows how to flatten an Array
of type [[Int]]
to type [Int]
using flatMap(_:)
:
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let flattenArray = array.flatMap({ (element: [Int]) -> [Int] in
return element
})
print(flattenArray) // prints [1, 2, 3, 4, 5, 6, 7, 8, 9]
Array
's joined()
methodArray
's has a method called joined()
. joined()
has the following declaration:
func joined() -> FlattenSequence<Array<Element>>
Returns the elements of this sequence of sequences, concatenated.
The following Playground sample code shows how to flatten an Array
of type [[Int]]
to type [Int]
using joined()
:
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let flattenCollection = array.joined()
let flattenArray = Array(flattenCollection)
print(flattenArray) // prints [1, 2, 3, 4, 5, 6, 7, 8, 9]
Array
's reduce(_:_:)
methodSwift Array
has a reduce(_:_:)
method with the following declaration:
func reduce<Result>(_ initialResult: Result, _ nextPartialResult: (Result, Element) throws -> Result) rethrows -> Result
Returns the result of combining the elements of the sequence using the given closure.
The following Playground sample code shows how to flatten an Array
of type [[Int]]
to type [Int]
using reduce(_:_:)
:
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let flattenArray = array.reduce([], { (result: [Int], element: [Int]) -> [Int] in
return result + element
})
print(flattenArray) // prints [1, 2, 3, 4, 5, 6, 7, 8, 9]
As an alternative to reduce(_:_:)
, you can use reduce(into:_:)
:
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let flattenArray = array.reduce(into: [Int]()) { (result: inout [Int], element: [Int]) in
result += element
}
print(flattenArray) // prints [1, 2, 3, 4, 5, 6, 7, 8, 9]
Upvotes: 9
Reputation: 23407
Flatten function in Array :
let x = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let y = Array(x.flatten())
print(y)
flatMap function in Array :
let x = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
let y = x.flatMap({$0})
print(y)
Your Output :
For more : Array in Swift
Upvotes: -1