CODEWITHSUNDEEP
arraysajaxcodeigniter
meph
meph

Reputation: 209

Send array with ajax in codeigniter

How can i pass an array with ajax? My code in view:

$(document).ready(function(){

  $('#btn-send').click(function(){

    var value = {
              'name': $('#name').val(),
              'phone': $('#phone').val(),
              'mail': $('#mail').val(),
          };

    $.ajax({
        type: 'POST',
        url: '<?php echo site_url('customer_add/test'); ?>',
        data: value,
        success: function(resp){
            $('#error').html(resp);
        }
    });
  });
});

My test method:

public function test5(){
    $data = $this->input->post["value"];
    $name = $data['name'];
    echo $name; 
}

In params - in the inspect element - there are data but in response, there's nothing to return. What's wrong? Thank's in advance.

Upvotes: 1

Views: 4843

Answers (2)

Benyi
Benyi

Reputation: 952

First, you can handle your error at the error section of $.ajax by error: function(xhr) {},

$.ajax({
    type: 'POST',
    url: '<?php echo site_url('customer_add/test'); ?>',
    data: {
        name: $('#name').val(),
        phone: $('#phone').val(),
        mail: $('#mail').val()
    },
    error: function(xhr) {
        alert('error');
    },
    success: function(resp){
        $('#error').html(resp);
    }
});

Next, type: 'POST' means the form would post the fields out by the method POST.
So that we can catch them by $_REQUEST or $_POST.

In Codeigniter, the way to catch the posted fields is $this->input->post('name');.
There's an error in your syntax.

public function test5(){
    $data['name'] = $this->input->post('name');
    $data['phone'] = $this->input->post('phone');
    $data['mail'] = $this->input->post('mail');

    echo $data;
}

Hope it would be help.

Upvotes: 1

quarksera
quarksera

Reputation: 101

You send data through ajax and you create a array of value with key:value pair when data send to server using post so you can get this whole array in one single variable using.

public function test5(){
    $data = $this->input->post();
    $name = $data['name']; echo $name;
    $phone = $data['phone']; echo $phone;
    $mail = $data['mail']; echo $mail;
}

you dont have to mention value key in $data = $this->input->post["value"];

and the second thing

you are writing wrong syntax $this->input->post["value"];

the write syntax is $this->input->post("value");

but in $this->input->post("value"); case you cant get value because there is no key with value name.

Upvotes: 0

Related Questions