CODEWITHSUNDEEP
arraysbashexpansion
Anton Tarasenko
Anton Tarasenko

Reputation: 8475

Inline expansion of arrays in bash

I'm trying to expand an array in bash:

FILES=(2009q{1..4})
echo ${FILES[@]}
echo ${FILES[@]}.zip

Output is:

2009q1 2009q2 2009q3 2009q4
2009q1 2009q2 2009q3 2009q4.zip

But how can I expand the last line as in echo 2009q{1..4}.zip expansion, so that the last line looked like:

2009q1.zip 2009q2.zip 2009q3.zip 2009q4.zip

... but using array FILES?

Upvotes: 3

Views: 558

Answers (2)

Cyrus
Cyrus

Reputation: 89009

FILES=(2009q{1..4})
echo ${FILES[@]/%/.zip}

Output:

2009q1.zip 2009q2.zip 2009q3.zip 2009q4.zip

From Bash's Parameter Expansion:

${parameter/pattern/string}: The pattern is expanded to produce a pattern just as in filename expansion. Parameter is expanded and the longest match of pattern against its value is replaced with string. If pattern begins with '/', all matches of pattern are replaced with string. Normally only the first match is replaced. If pattern begins with '#', it must match at the beginning of the expanded value of parameter. If pattern begins with '%', it must match at the end of the expanded value of parameter. If string is null, matches of pattern are deleted and the / following pattern may be omitted. If parameter is '@' or '', the substitution operation is applied to each positional parameter in turn, and the expansion is the resultant list. If parameter is an array variable subscripted with '@' or '', the substitution operation is applied to each member of the array in turn, and the expansion is the resultant list.

Upvotes: 6

anubhava
anubhava

Reputation: 786329

You can use printf:

printf "%s.zip " "${FILES[@]}"

2009q1.zip 2009q2.zip 2009q3.zip 2009q4.zip

Upvotes: 2

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