Reputation:
I am writing my first project in PHP and I have a problem connected with jQuery.
In my test.html page I have a <div>
and in there are 3 buttons, one above the other.
When the user clicks the top button, I want a new <div>
created under that button with a textbox and one new button (x button). The other 2 buttons must be moved.
After clicking x button, everything should return to its initial state.
On the jQuery homepage if you click the “run code” button you will see what I want.
Thanks for any advice.
Upvotes: -1
Views: 103
Reputation: 901
The sample code from the front page:
$("p.neat").addClass("ohmy").show("slow");
What this is doing is referencing the p tag that has a class of "neat", adding a class of "ohmy" (which is likely styled in CSS), and causing the event "show" to happen slowly.
The p tags existed already, and were hidden (likely using a CSS attribute of display:none) and then shown using JQuery.
JQuery has great documentation. I would suggest that you go through some of the tutorials and get a feel for how it works.
Upvotes: 1