Reputation: 211
I want to convert a string from a dataframe to datetime.
dfx = df.ix[:,'a']
dfx = pd.to_datetime(dfx)
But it gives the following error:
ValueError: day is out of range for month
Can anyone help?
Upvotes: 20
Views: 87462
Reputation: 511
Well in my case
year = 2023
month = 2
date = datetime.date(year, month, 30)
got me this error because February month has 29 or 28 days in it. Maybe that point helps someone
Upvotes: 4
Reputation: 863721
Maybe help add parameter dayfirst=True
to to_datetime
, if format of datetime is 30-01-2016
:
dfx = df.ix[:,'a']
dfx = pd.to_datetime(dfx, dayfirst=True)
More universal is use parameter format
with errors='coerce'
for replacing values with other format
to NaN
:
dfx = '30-01-2016'
dfx = pd.to_datetime(dfx, format='%d-%m-%Y', errors='coerce')
print (dfx)
2016-01-30 00:00:00
Sample:
dfx = pd.Series(['30-01-2016', '15-09-2015', '40-09-2016'])
print (dfx)
0 30-01-2016
1 15-09-2015
2 40-09-2016
dtype: object
dfx = pd.to_datetime(dfx, format='%d-%m-%Y', errors='coerce')
print (dfx)
0 2016-01-30
1 2015-09-15
2 NaT
dtype: datetime64[ns]
If format is standard (e.g. 01-30-2016
or 01-30-2016
), add only errors='coerce'
:
dfx = pd.Series(['01-30-2016', '09-15-2015', '09-40-2016'])
print (dfx)
0 01-30-2016
1 09-15-2015
2 09-40-2016
dtype: object
dfx = pd.to_datetime(dfx, errors='coerce')
print (dfx)
0 2016-01-30
1 2015-09-15
2 NaT
dtype: datetime64[ns]
Upvotes: 28