CODEWITHSUNDEEP
iosobjective-cuitableviewnsnotification
Abdul Rehman
Abdul Rehman

Reputation: 2456

Pass Message using NSNotification from UITableView row selection to uiViewController

i'm new in IOS. i look for solution for over a day but all available solution work within a single UIViewConntroller but when i did it between uiTableView row selection and UIViewConntroller as Observer then the Selector is not called by Observer.

On row Selection in uitableviewcontroller

 NSDictionary * dict =[NSDictionary dictionaryWithObject:@"Ravi" forKey:@"name"];
NSNotification * notification =[[ NSNotification alloc] initWithName:@"NOTIFICATION" object:nil userInfo:dict];

**In UIViewController on viewdidload **

[[NSNotificationCenter defaultCenter] addObserver:self
                                         selector:@selector(receivedNotification:)
                                             name:@"NOTIFICATION" object:nil];

**SelectorAction in uiviewcontroller **

    -(void) receivedNotification:(NSNotification*) notification
{

    NSLog(@"Notification  Received ");
}

Upvotes: 1

Views: 999

Answers (7)

Abdul Rehman
Abdul Rehman

Reputation: 2456

There is no problem in any of the above code infect i'm doing it in wrong way. I'm posing notification first and observing after posting notification. But i have to observe first and post notification after it.

I solve this problem as :

In AppDelegate didFinishLaunchingWithOptions: load viewControler first so that the observer is ready to get notification(inViewDidLoad) and after that Show/navigate to tableView And then it work perfect.This isn't the proper way but work for me. :)

Also Read out the @karthik and @Priyanka Mistry Answers. Helped me to solve the problem.

Upvotes: 1

karthik
karthik

Reputation: 621

hi @Abdul Rehman Warraich, i got your problem. you are posting notification in one view, and trying to observe it an another view. but what happens is, in the second view your observer is not ready (not loaded) to get the notification what you sent.

once you landed in the second view, that time itself observer is loaded.so it obviously will miss the notification.

so whenever you do push and pop, observer will loading as new one. so every time it will fail to observe it.

HINT: Try to load observer in your second view , before you fire the notification. Hope it will help you to debug.

Upvotes: 1

Sanjeet Verma
Sanjeet Verma

Reputation: 571

Try this i hope it would be helpful:

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

- (void)viewDidLoad {
    [super viewDidLoad];
    myData = [[NSMutableArray alloc]init];
    myData = [[NSMutableArray alloc]initWithObjects:@"india",@"Japan",@"pakistan",@"srilanka", nil];
    _mytableView.delegate = self;
    _mytableView.dataSource = self;
}

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

-(void)viewWillAppear:(BOOL)animated
{
        [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(receivedNotification:)name:@"NOTIFICATION" object:nil];
}
-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
    return myData.count;
}

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *const identifier = @"Cell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:identifier];

    cell.textLabel.text = [myData objectAtIndex:indexPath.row];

    return cell;
}

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    NSDictionary * dict =[NSDictionary dictionaryWithObject:@"Ravi" forKey:@"name"];
    [[NSNotificationCenter defaultCenter] postNotificationName:@"NOTIFICATION" object:nil userInfo:dict];
}


-(void) receivedNotification:(NSNotification*) notification {
    NSLog(@"Notification  Received ");
}

@end

in viewcontroller.h file 

#import <UIKit/UIKit.h>

@interface ViewController : UIViewController<UITableViewDelegate,UITableViewDataSource>
{

    NSMutableArray *myData;
}

@property (weak, nonatomic) IBOutlet UITableView *mytableView;

@end

Upvotes: 0

Duncan C
Duncan C

Reputation: 131418

Stefos' answer is the usual way to post a notification, but if you do want to create a notification object manually, you then need to post it:

NSDictionary * dict =[NSDictionary dictionaryWithObject:@"Ravi" forKey:@"name"];
NSNotification * notification =[[ NSNotification alloc] 
  initWithName:@"NOTIFICATION" 
  object:nil userInfo:dict];
[[NSNotificationCenter defaultCenter] postNotification: notification];

(I don't think I've ever done it in 2 steps like this. I always use one of the forms that takes a name, option, and userInfo and creates and posts the notification in one call.)

Upvotes: 0

Priyanka Wadher Mistry
Priyanka Wadher Mistry

Reputation: 464

In UITableViewController when you select the row Post Notification: 

NSDictionary * dict =[NSDictionary dictionaryWithObject:@"Ravi" forKey:@"name"];  
[[NSNotificationCenter defaultCenter] postNotificationName:@"NOTIFICATION" object:nil userInfo:dict];

In UIViewController viewDidLoad method addObserver:

[[NSNotificationCenter defaultCenter] addObserver:self
                                         selector:@selector(receivedNotification:)
                                             name:@"NOTIFICATION" object:nil];

Write method in UIViewController: 

-(void)receivedNotification:(NSNotification*) notification
{
    NSLog(@"Notification  Received ");
}

Check if UIViewController's instance is there in the stack? otherwise you will not get the response.

Upvotes: 1

neha
neha

Reputation: 167

Use tableView didSelectRowAtIndexPath Delegate:

-(void) tableView:(UITableView *)tableView didSelectRowAtIndexPath:    (NSIndexPath *)indexPath
{
    //Post notification here
}

Upvotes: 0

stefos
stefos

Reputation: 1235

You don't have to creat a NSNotification object. Just post the notification when row selected :

  NSDictionary * dict =[NSDictionary dictionaryWithObject:@"Ravi" forKey:@"name"];
 [[NSNotificationCenter defaultCenter] postNotificationName:@"NOTIFICATION" object:nil userInfo:dict];

Upvotes: 1

Related Questions