Reputation: 189
I have a tableview like this
I want to take the link and pass it to another controlview.
Here what i have done
func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
let linktopass = classes[indexPath.row].valueForKey("link")
print(linktopass)
func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
let thirdVC: web = segue.destinationViewController as! web
thirdVC.link = linktopass as! String
But it does not work.
Here is my print's output.
Optional( http://blablabla )
Upvotes: 0
Views: 776
Reputation: 27428
If think you forget to performsegue
in didSelectRowAtIndexPath
.
prepareForSegue
is get called before you performsegue
. if you are not performing segue then your prepareForSegue
will not called.
so, in didSelectRowAtIndexPath
, add code like,
performSegueWithIdentifier("goToNextVC", sender: self) //your segue identifier here
//goToNextVC is segue identifier set from attribute inspector from storyboard
Make sure you have set segue identifier from attribute inspector
.
You can set identifier like,
select segue - click attribute inspector - write identifier in it - press enter
Hope this will help :)
Upvotes: 1