CODEWITHSUNDEEP
javaxmlxsltsaxon
A Coder Gamer
A Coder Gamer

Reputation: 840

Saxon implementation for Stream of data

In my code below, I’m modifying the XML file with XSLT using SAXON

import java.io.File;

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class SaxonImplementation {

  public static void simpleTransform(String sourcePath, String xsltPath,
      String resultDir) {
    TransformerFactory tFactory = TransformerFactory.newInstance();
    try {
      Transformer transformer = tFactory
          .newTransformer(new StreamSource(new File(xsltPath)));
      transformer.transform(new StreamSource(new File(sourcePath)),
          new StreamResult(new File(resultDir)));
    } catch (Exception e) {
      e.printStackTrace();
    }
  }

  public static void main(String[] args) {
    System.setProperty("javax.xml.transform.TransformerFactory",
        "net.sf.saxon.TransformerFactoryImpl");
    simpleTransform("first.xml", "newxsl.xslt", "second.xml");
  }
}

Now instead of modifying the XML file, I want to modify an XML string. How shall I proceed here? The transformer.transform method requires an XML source file and the result file. How can I provide an XML string instead of a file and get the results in the form of Stream?

Upvotes: 2

Views: 539

Answers (1)

wero
wero

Reputation: 32980

You can create a StreamSource for a java.io.Reader therefore wrap the XML string in a StringReader and then in a StreamSource and pass that to the transformer:

String xml = ...
transformer.transform(new StreamSource(new StringReader(xml)), ...

Same is true for the StreamResult, you can use any OutputStream or Writer to create a StreamResult.

And this works for any Trax implementation not just for Saxon.

Upvotes: 3

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