CODEWITHSUNDEEP
javaregex
ZouIou
ZouIou

Reputation: 35

regex, characters separated by comma

I want check the format of a String. The formats possible are :

-"AZERTY"
-"AZERTY,REGULAR,AKILO"

I make this but I'm not sure :

String formatAttributes = "^[a-zA-Z0-9](,[a-zA-Z0-9])?*$";

It's correct ?

Upvotes: 2

Views: 187

Answers (2)

Ro Yo Mi
Ro Yo Mi

Reputation: 15010

There are several plausible solutions here. Assuming that you only want to match exactly your two examples AZERTY and AZERTY,REGULAR,AKILO where the characters can be any a-z.

^([a-z0-9]+(?:,[a-z0-9]+,[a-z0-9]+)?)$

Regular expression visualization

Note: this expression assumes the use of the case insensitive flag.

Live Demo

https://regex101.com/r/yP6lX6/1

Upvotes: 0

Nicolas Filotto
Nicolas Filotto

Reputation: 45005

Here is how to proceed:

Pattern pattern = Pattern.compile("\\w+(,\\w+)*");
System.out.println(pattern.matcher("AZERTY").matches());
System.out.println(pattern.matcher("AZERTY,REGULAR,AKILO").matches());

Output:

true
true

NB: \w is a word character: [a-zA-Z_0-9] which means that underscore has been added to your initial regular expression, if you don't want it, the regexp will be [a-zA-Z0-9]+(,[a-zA-Z0-9]+)*

Upvotes: 2

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