Reputation: 3812
Can I get http
page as seen in browser - fully formed after javascripts
are run? No need to submit data and press buttons. IMHO it's standard task, where can I see example to run all scripts and get result?
Via:
u = urllib.request.urlopen('https://www.*')
data = u.read()
I get page as seen if I choose view source in browser. However, when I inspect elements on page, I see how code expands, e.g.:
<div class="js-events-container"></div>
expands to:
<div class="js-events-container"> <table class="zebra noBorderTbl" style="width: 100%;">
<tbody><tr>
<th>1</th>
<th>2</th>
<th>3</th>
</tr>
...
</tr>
</tbody></table>
</div>
Upvotes: 0
Views: 54
Reputation: 3812
I now load page using selenium
, then get page_source
. In spite of name, page_source
give not page source, but page result after java scripts are run.
Upvotes: 0
Reputation: 2179
You can also give a look to this particular library dryscape. It is javascript aware as per documentation.
Upvotes: 0
Reputation: 51
i see js in the class name, it is probably javascript, i think there isn't a way to get the full page with urllib. you need to pull the site after the javascript starts. you will need selenium or phantomjs to do the job.
Upvotes: 1