CODEWITHSUNDEEP
c#wpfwindowsxaml
user2837961
user2837961

Reputation: 1555

Focus window of my application

I have a WPF application with two xaml windows from two different dlls. Both Dlls load at the same time and display their windows which works fine. There is also another window of a third party software.

Please note that all windows are borderless (windowstyle = none).

My problem is that I want the focus to remain with one of the two xaml windows. As soon as the focus goes to the third party software window, I want any one of the xaml window to regain it. How can I achieve this? Maybe in OnDeactivate event?

    public void OnMainGUIDEactivate(object sender, EventArgs e)
    {
        Activate();
    }

// Tried to add application deactivate

    public MyFirstView()
    {
        InitializeComponent();
        Application.Current.Deactivated += AppDeactivated;

    }

    void AppDeactivated(object sender, EventArgs e)
    {
        // Application deactivated
        Activate();
    }

Upvotes: 0

Views: 712

Answers (3)

user2837961
user2837961

Reputation: 1555

I resolved this problem by a work around.

On both xamls I used Topmost="True"

Upvotes: 0

Fabrizio Stellato
Fabrizio Stellato

Reputation: 1891

There's a MVVM / Blend approach:

Declare this on your window:

xmlns:i="http://schemas.microsoft.com/expression/2010/interactivity"                
xmlns:ei="http://schemas.microsoft.com/expression/2010/interactions"

Then call the focus method on Deactivated event of your window

 <i:Interaction.Triggers>
    <i:EventTrigger EventName="Deactivated" >
        <ei:CallMethodAction MethodName="Focus" TargetObject="{Binding ElementName=mywindow}" />
    </i:EventTrigger>
</i:Interaction.Triggers>

Upvotes: 0

BugFinder
BugFinder

Reputation: 17858

The event you're after is : Application.Current.Deactivated

you can then call it to reactivate, so you can then call either of your forms with whatever.Activate() and it will bring it back

Upvotes: 1

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