CODEWITHSUNDEEP
pythonbashcurl
technewbie
technewbie

Reputation: 21

Converting curl command to python

I am new to Python. I am trying to convert below bash script command to Python using subprocess. I don't get any output nor do I see any failure when I execute my Python script.

This is the bash command that needs to be ported to Python.

curl -u 'lawn:oldlawn!' -k -s -H 'Content-Type: application/json' -X GET 'https://192.168.135.20:443/api/json/v2/types/dev-objs/1'

My python code:

get_curl():
  curl = """curl -u 'lawn:oldlawn!' -k -s -H 'Content-Type: application/json' -X GET 'https://192.168.135.20:443/api/json/v2/types/dev-objs/1'"""

  args = curl.split()

  process = subprocess.Popen(args, shell=False, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

  stdout, stderr = process.communicate()
  print stdout
  print stderr

# End of python code

After I execute get_curl(), print stdout and print stderr does not print anything though dev-objs/1 exists.

When I execute the same command as bash command it works and I see the REST API output.

Can anyone help me what may be going wrong here? Thanks

Upvotes: 0

Views: 602

Answers (2)

Padraic Cunningham
Padraic Cunningham

Reputation: 180401

You could use requests:

headers = {
    'Content-Type': 'application/json',
}


import requests

proxies = {
  'https': 'https://lawn:[email protected]:443',
}

req = requests.get('https:...', proxies=proxies, verify=False, headers=headers)

I don't think there is a -s flag for requests as no data will be output unless you print what is returned with req.json().

I thought you had a capital U not a u so all you really need is to do is to use basic-authentication passing auth = (user, pass), set verify=False as per Brendans answer.

Why your subprocess code did not work was because you have some args quoted like "'lawn:oldlawn!'", what you want is:

args = ['curl',
 '-u',
 'lawn:oldlawn!',
 '-k',
 '-s',
 '-H',
 'Content-Type: application/json',
 '-X',
 'GET',
 'https://192.168.135.20:443/api/json/v2/types/dev-objs/1']

process = subprocess.Popen(args, shell=False,   stdout=subprocess.PIPE, stderr=subprocess.PIPE)

stdout, stderr = process.communicate()

Upvotes: 3

Brendan Abel
Brendan Abel

Reputation: 37509

Using requests will make your http(s) requests far simpler:

import requests


response = requests.get('https://192.168.135.20:443/api/json/v2/types/dev-objs/1', 
                        verify=False, auth=('lawn', 'oldlawn!'))
print response.json()

Upvotes: 1

Related Questions