CODEWITHSUNDEEP
phpdatetimephp-5.3
Harea Costicla
Harea Costicla

Reputation: 817

Add number of days of an existing days

I have a problem and I don't understand where it is : So If I do : 

$end_date   = date('Y-m-d H:i:s',strtotime("+ $frequency days")); --> it works

If I do : 

$end = $o_user->end;
$o_user->end  = date($end, strtotime("+ $frequency days")); ---> not work

I tested and the 2 dates have the format : Y-m-d H:i:s Where is my error ? Please help me. Thx in advance

Upvotes: 0

Views: 54

Answers (4)

Viktor Koncsek
Viktor Koncsek

Reputation: 574

Date's first param is the format, not an another date.

It should be something like this: 

$o_user->end  = date("Y-m-d H:i:s", strtotime($end . " +$frequency days"));

Upvotes: 2

Brijal Savaliya
Brijal Savaliya

Reputation: 1091

You can use below code 

$i_frequency = 4;
$end = '2016-05-23 10:48:42';
echo "==" . date('Y-m-d', strtotime("+$i_frequency days", strtotime($end)));

OR 

$i_frequency = 4;
$end = '2016-05-23 10:48:42';
echo "==" . addDate($end, $i_frequency);
function addDate($date, $day)//add days
{
    $sum = strtotime(date("Y-m-d", strtotime("$date")) . " +$day days");
    $dateTo = date('Y-m-d', $sum);
    return $dateTo;
}

Upvotes: 0

Raghav Patel
Raghav Patel

Reputation: 843

Change to $o_user->end = date('Y-m-d H:i:s', strtotime($end, "+". $frequency. "days"));

Upvotes: 0

DonCallisto
DonCallisto

Reputation: 29932

Maybe you just want to do

$o_user->end->modify("+ $frequency days");

It's even more readable and compact.

BTW your error is that date() function expect as first parameter a string (the date format)

Upvotes: 0

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