Reputation: 153
I'm still very new to appcelerator but I'm trying to do a small experiment with geolocation. I have some code similar to below, which returns the long and lat to the console. What I would like to is get the long and lat and append them to a URL, e.g http://www.mywebsite.com/lat/long.
I've tried creating a simple alert to show me the current location in the but all it says is Alert: [object GeolocationModule].
Could somebody point me in the right direction so I can learn some more? Thank you
if (Ti.Geolocation.locationServicesEnabled) {
Titanium.Geolocation.purpose = 'Get Current Location';
Titanium.Geolocation.getCurrentPosition(function(e) {
if (e.error) {
Ti.API.error('Error: ' + e.error);
} else {
Ti.API.info(e.coords);
}
});
} else {
alert('Please enable location services');
}
Upvotes: 0
Views: 162
Reputation: 4055
This is how you need to follow the API documentation:
You can have a look at the LocationResults page: https://docs.appcelerator.com/platform/latest/#!/api/LocationResults which leads you to LocationCoordinates: https://docs.appcelerator.com/platform/latest/#!/api/LocationCoordinates
There you can see, that you can use e.coords.latitude
or longitude
to get the values. Or have a look at the console output. It should show you a JSON output with the key-value pairs.
Once you have the values you can create a HTTP request (demo: https://docs.appcelerator.com/platform/latest/#!/guide/HTTPClient_and_the_Request_Lifecycle) and open your page:
var url = "https://www.appcelerator.com/"+e.coords.longitude+"/"+e.coords.latitude;
var xhr = Ti.Network.createHTTPClient({
onload: function(e) {
// this function is called when data is returned from the server and available for use
// this.responseText holds the raw text return of the message (used for text/JSON)
// this.responseXML holds any returned XML (including SOAP)
// this.responseData holds any returned binary data
Ti.API.debug(this.responseText);
alert('success');
},
onerror: function(e) {
// this function is called when an error occurs, including a timeout
Ti.API.debug(e.error);
alert('error');
},
timeout:5000 /* in milliseconds */
});
xhr.open("GET", url);
xhr.send(); // request is actually sent with this statement
or if you plan to use more request have a look at RESTe (https://github.com/jasonkneen/RESTe) which is an awesome library that makes it easy to create API requests
Upvotes: 2