Reputation: 1323
I have to change the color of circle to be gradient
<div class="loader loader--style3" title="2">
<svg version="1.1" id="loader-1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px"
width="80px" height="80px" viewBox="0 0 50 50" style="enable-background:new 0 0 50 50;" xml:space="preserve">
<path fill="#070e1a" d="M43.935,25.145c0-10.318-8.364-18.683-18.683-18.683c-10.318,0-18.683,8.365-18.683,18.683h4.068c0-8.071,6.543-14.615,14.615-14.615c8.072,0,14.615,6.543,14.615,14.615H43.935z">
<animateTransform attributeType="xml"
attributeName="transform"
type="rotate"
from="0 25 25"
to="360 25 25"
dur="0.6s"
repeatCount="indefinite"/>
</path>
</svg>
</div>
Upvotes: 1
Views: 1392
Reputation: 13199
I think it is clear enough on the tutorial that @Harry posted before but I update your code here with the styles applied.
Just add a definition of your linear gradient and after make reference on the fill
property of your circle.
I do not know what are exactly the colours that you want to use so just change darkblue
and lightblue
of the linear gradient definition to your custom colours.
<div class="loader loader--style3" title="2">
<svg version="1.1" id="loader-1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px"
width="80px" height="80px" viewBox="0 0 50 50" style="enable-background:new 0 0 50 50;" xml:space="preserve">
<defs>
<linearGradient id="customGradient">
<stop offset="95%" stop-color="#123354"/>
<stop offset="5%" stop-color="#070f1c"/>
</linearGradient>
</defs>
<path fill="url(#customGradient)" d="M43.935,25.145c0-10.318-8.364-18.683-18.683-18.683c-10.318,0-18.683,8.365-18.683,18.683h4.068c0-8.071,6.543-14.615,14.615-14.615c8.072,0,14.615,6.543,14.615,14.615H43.935z">
<animateTransform attributeType="xml"
attributeName="transform"
type="rotate"
from="0 25 25"
to="360 25 25"
dur="0.6s"
repeatCount="indefinite"/>
</path>
</svg>
</div>
Upvotes: 1