CODEWITHSUNDEEP
rubyrequire
never_had_a_name
never_had_a_name

Reputation: 93276

Require file without executing code?

Here I have two files:

file.rb

def method
  puts "This won't be outputted."
end

puts "This will be outputted."

main.rb

require "./file"

When running main.rb it will load all the code inside file.rb so I will get "This will be outputted." on the screen.

Is it possible to load a file without having it to run the code?

Cause I want to load all the methods (in modules and classes too) without having to execute code outside these scopes.

Upvotes: 20

Views: 6426

Answers (3)

megas
megas

Reputation: 21791

I don't think modifying file is good idea - there are could be a lot of files like this one or these files belong to customer and a ton of another reasons.

Ruby is good at metaprogramming so why don't use this feature?

It could be like this.

Create file with fake module and put here the file.

File.open("mfile.rb","w") do |f|
  f.write "module FakeModule
"
  f.write File.open("file.rb").read
  f.write "
end"
end

Then load this file:

require "/.mfile.rb

and accessing to the method:

FakeModule::method

Upvotes: 1

stephenr
stephenr

Reputation: 1173

the if __FILE__ == $0 is nice, but a way more in keeping with ruby's Object Oriented approach is to put all the methods you want access to in a class (as class methods), and then call them from main.rb.

e.g.

file.rb

class MyUtils
    def self.method
        puts "this won't be outputted"
    end
end

and then in main.rb

require "/.file.rb"

and when you want to use your utility methods:

MyUtils.method

Upvotes: 8

sepp2k
sepp2k

Reputation: 370415

Is it possible to load a file without having it to run the code?

No, everything in a ruby file is executable code, including class and method definitions (you can see this when you try to define a method inside an if-statement for example, which works just fine). So if you wouldn't execute anything in the file, nothing would be defined.

You can however tell ruby that certain code shall only execute if the file is run directly - not if it is required. For this simply put the code in question inside an if __FILE__ == $0 block. So for your example, this would work:

file.rb

def method
  puts "This won't be outputted."
end
if __FILE__ == $0
  puts "This will not be outputted."
end

main.rb

require "./file"

Upvotes: 40

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