set of integers as input to print sum of their cubes

Question

I am trying to solve this question. I tried many different ways, I get the correct output but the testcases are not passed(I dont know what are those testcases). I cant figure what is wrong.

Question:

Given a set of integers (separated by space), write a program to print the sum of their cubes.

Sample Input:

1 2 3 4 5

Sample Output:

225

Sample Input:

1 2

Sample Output:

9

Solution 2:

import java.io.*;
import java.util.*;

class Test{

    public static void main(String []args)
    {
        int num,sum=0;

        Scanner sc=new Scanner(System.in);
        String data=sc.nextLine();

        Scanner sc2=new Scanner(data);
        while(sc2.hasNextInt())
        {
            num=sc2.nextInt();
            sum=sum+num*num*num;
        }

        System.out.print(sum);
    }
}

Answer 1

Used long instead of int. Thanks to Andreas and Matsev for the BigInteger idea.

import java.util.*;
class Test{
    public static void main(String []args)
    {
        long num,sum=0;

        Scanner sc=new Scanner(System.in);
        String data=sc.nextLine(); 
        Scanner sc2=new Scanner(data);
        while(sc2.hasNextInt())
        {
            num=sc2.nextInt();
            sum=sum+num*num*num;
        }
        System.out.println(sum);
    }
}

Answer 2

    public static void main(String args[])
    {
         long num,count=0;
         Scanner in=new Scanner(System.in);
         while(in.hasNextInt())
         {
             num=in.nextInt();
             count+=Math.pow(num,3);
         }
         System.out.println(count);
    }

or

    public Static vid main(String args[])
    {
         long count;
         Scanner in=new Scanner(System.in);
         String s=in.nextLine();
         String[] t=s.split(" ");
         for(i=0;i<t.length;i++)
         {
             count+=Math.pow(Integer.parseInt(t[i]),3);
         }
         System.out.println(count);
    }

Answer 3

import java.util.*;

class csum

{

public static void main(String args[])

{

 Scanner in=new Scanner(System.in);

long csum=0;

 while(in.hasNextInt())

{

  csum=csum+(long)Math.pow(in.nextInt(),3);

}  

System.out.println(csum);

}

}

Answer 4

Update (by Andreas): Added boilerplate imports since @Ash seems unable to figure that out.

If you would like an implementation in more functional style (using Java 8+ streams), here is another suggestion:

import java.math.BigInteger;
import java.util.Arrays;
import java.util.Scanner;

public class Test {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        String line = scan.nextLine();
        String[] numbers = line.split("\\s+");

        BigInteger sum = Arrays.asList(numbers)
                .stream()
                .map(BigInteger::new)
                .map(bigInteger -> bigInteger.pow(3))
                .reduce(BigInteger.ZERO, BigInteger::add);

        System.out.println(sum);
    }
}

---

Update: After @Andreas comments, the implementation can be even shorter:

import java.math.BigInteger;
import java.util.Scanner;
import java.util.regex.Pattern;

public class Test {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        String line = scan.nextLine();

        BigInteger sum = Pattern.compile("\\s+")
                .splitAsStream(line)
                .map(s -> new BigInteger(s).pow(3))
                .reduce(BigInteger::add)
                .orElse(BigInteger.ZERO);

        System.out.println(sum);
    }
}

Answer 5

I modified my answer according to your needs. Now it gives sum of cubes of numbers in given input which are separated by spaces. Check this :-

import java.math.BigInteger;
import java.util.ArrayList;
import static java.util.Collections.list;
import java.util.List;
import java.util.Scanner;

public class SumOfCubes {
public static void main(String[] args) {
    Scanner in=new Scanner(System.in);
    String integers="";
    Integer num=0;
    BigInteger cube;
    BigInteger sum=new BigInteger("0");

    System.out.println("Enter Integers seperated by space");
    integers=in.nextLine();

    List<Integer> list = new ArrayList<Integer>();
    for (String s : integers.split("\\s")) {  
        list.add(Integer.parseInt(s));  
    }
    list.toArray();

    for(int i=0;i<list.size();i++){
        num=list.get(i);
        cube=BigInteger.valueOf(num*num*num);
        sum=sum.add(cube);
    }

    System.out.println("Sum of Cubes of numbers in given input = "+sum);
}

}

Hope it helps.

Answer 6

I have changed your Solution 2 a little bit. Could you please confirm whether this passes the test or not.

 import java.math.BigInteger;
 import java.util.Scanner;

 public class Test{

 public static void main(String []args)
    {

        BigInteger sum=new BigInteger.ZERO;

        Scanner sc=new Scanner(System.in);
        String data=sc.nextLine();

        Scanner sc2=new Scanner(data);

        while(sc2.hasNextInt())
        {
            BigInteger num=new BigInteger(String.valueOf(sc2.nextInt()));
            sum= sum.add(num.multiply(num).multiply(num));
        }

        System.out.print(sum);
    }
}

Answer 7

Your test cases most likely contain large integers as input. Use BigInteger to hold their cubes.