CODEWITHSUNDEEP
javascriptregex
Jim Peeters
Jim Peeters

Reputation: 2863

Why is this regular expression in javascript still allowing special characters [a-zA-Z1-9 ]?

I don't want to allow special characters but this regular expression still allows them, what am I doing wrong?

When i type for name : '&é"é&'é"&'&é"'a' It still gives back 'true'

name.match(/[a-zA-Z1-9 ]/))

Upvotes: 3

Views: 1065

Answers (4)

Chetan Sanghani
Chetan Sanghani

Reputation: 2111

if(!/[^a-zA-Z0-9]/.test(name)) {
  // "your validation message"    
}

try this

Upvotes: 2

Santosh Jadi
Santosh Jadi

Reputation: 1527

This will work for you:

var nameregex = /^([A-Za-z0-9 ]$)/;
var name = document.getElementById('name').value;

if (!name.match(nameregex)) {
    alert('Enter Valid Name!!');
}

Upvotes: 1

Rhapsody
Rhapsody

Reputation: 6077

It returns true because the last character ('a') is ok. Your regex doesn't check whether the complete input matches the regex.

Try this one: ^[a-zA-Z1-9 ]*$

Upvotes: 3

Tushar
Tushar

Reputation: 87203

You need to use RegExp#test with anchors ^ and $.

/^[a-zA-Z1-9 ]+$/.test(name)

String#match return an array if match is found. In your case, a at the end of the string is found and array is returned. And array is truthy in the Javascript. I believe, the array is converted to Boolean, so it returned true.

Upvotes: 6

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