CODEWITHSUNDEEP
phpmysqldatemax
DaDu
DaDu

Reputation: 103

mysql. I want to get the max value of all rows with a specific date and use the corresponding fields

My table 'players_online'

id | count | date      | time  | day | max-players

0  | 55    | 26/05/16  | 13:00 | 5   | 300
1  | 33    | 26/05/16  | 13:10 | 5   | 300
2  | 43    | 26/05/16  | 13:20 | 5   | 300
3  | 100   | 27/05/16  | 13:00 | 6   | 300
4  | 43    | 27/05/16  | 13:10 | 6   | 300
5  | 56    | 27/05/16  | 13:20 | 6   | 300

desired output (todays highest count)

id | count | date      | time  | day | max-players

3  | 100   | 27/05/16  | 13:00 | 6   | 300

Also

(yesterdays highest count)

id | count | date      | time  | day | max-players

0  | 55    | 26/05/16  | 13:00 | 5   | 300

And

(Higest total count)

id | count | date      | time  | day | max-players

3  | 100   | 27/05/16  | 13:00 | 6   | 300

My knowledge of mysql has gotten rusty and I have no idea how to get it right. previously I tried the following which didn't select the right time.

SELECT MAX(count) AS maxcount, date, time FROM players_online WHERE date='".date('d-m-y')."'

I'm building a little stats page where you can view the highest player count of a minecraft server today (until now), yesterday and the highest player count of all time with their corresponding date, time, day and max-players.

Hope somebody can give me a hand.

Upvotes: 0

Views: 33

Answers (1)

Styphon
Styphon

Reputation: 10447

You can just do a simple query that orders by count and is limited to 1.

SELECT * FROM players_online WHERE date = '27/05/2016' ORDER BY count DESC LIMIT 1

That should get you the highest count.

Upvotes: 3

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