CODEWITHSUNDEEP
jsonscalakey-value
codehammer
codehammer

Reputation: 885

Idiomatic way of converting string of key value pairs to a JSON string (Scala)

I'm trying to convert a string of key value pairs to a JSON string. The only thing I know about the string of KV pairs is the format of the string i.e. space seperated, comma seperated etc.. For e.g. I don't control over the number or type of the keys coming in as input.

Here is what I came up with and wanted to see if this approach looks OK / awesome / awkward. Would appreciate if there is better alternative than this.

INPUT : clientIp="1.1.1.1" identifier="a.b.c" key1=10 key2="v3"

final val KV_PATTERN = "(\"[^\"]*\"|[^,\\\"\\s]*)=(\"[^\"]*\"|[^,\\\"\\s]*)".r

val cMap = KV_PATTERN.findAllMatchIn(inputString).map(m => (m.group(1).trim(), m.group(2).trim())).toMap

val json = cMap.map { case (key, value) => if (!key.startsWith("\"")) s""""$key"""" + ":" + value else s"$key:$value" }.mkString("{", ",", "}")`

OUTPUT: {"clientIp":"1.1.1.1","identifier":"a.b.c","key1":10,"key2":"v3"}

Upvotes: 0

Views: 844

Answers (1)

chengpohi
chengpohi

Reputation: 14227

"{"+ inputString.split(" ").map{case i => val t = i.split("="); s""""${t(0).replaceAll("^\"|\"$", "")}": ${t(1)}"""}.mkString(",") + "}"

Maybe this is more cleaner.

Upvotes: 2

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