Reputation: 13626
I'm working through the Microcorruption CTF which uses an emulated MSP430 CPU.
I've seen several mov instruction examples like:
mov sp, r4 ; move value of stack pointer to register 4
mov #0xfffc, r15 ; move hex value fffc to r15
I'm trying to interpret:
mov.b #0x4f, 0x0(r15)
I assume mov.b is binary value of #0x4f, but I'm not sure what 0x0(r15)
indicates.
Upvotes: 11
Views: 16982
Reputation: 11075
It means use a byte operation:
The suffix .B at the instruction memonic will result in a byte operation
So only a byte of data will be copied from the source to the destination.
0x0(r15) is an indexed addressing mode, so use r15 + 0 bytes to specify the destination.
Upvotes: 17