Reputation: 679
It is possible to have a rectangle with 2 or more background colors? Something like 50% black, 50% red?
I want to make a health bar for showing the remained health. I thought I could make something like:
life = 100
width with green color = 99,98,....,0%
width with gray color = 0,1,...,100% (end of game)
Upvotes: 0
Views: 5795
Reputation: 82461
This can be done using a LinearGradient
as fill for the background
:
Region rect = new Region();
rect.setMaxSize(100, 20);
rect.setPrefSize(100, 20);
rect.setBackground(new Background(new BackgroundFill(new LinearGradient(0, 0, 1, 0, true, CycleMethod.NO_CYCLE,
new Stop(0.3, Color.GREEN),
new Stop(0.3, Color.RED)
), CornerRadii.EMPTY, Insets.EMPTY)));
Alternatively you can also do this using CSS:
rect.setId("myrect");
#myrect {
-fx-background-color: linear-gradient(to right, green 30%, red 30%);
}
Both versions fill the first 30% of the Rectangle
with green and the rest with red (horizontally).
Note that James_D's solution should be prefered. This is only for the sake of completeness.
LinearGradient
extends Paint
and therefore you could also assign it to the fill
property of a Rectangle
(or any other Shape
).
Upvotes: 2
Reputation: 209339
There are a bunch of different ways to do this. I'd probably prefer using the functionality already defined in a ProgressBar
and using CSS to style it to get the colors you want; or just use a regular Pane
and use two nested background colors and vary the insets. These and various other options using rectangles etc are shown in the demo below:
import javafx.animation.KeyFrame;
import javafx.animation.KeyValue;
import javafx.animation.Timeline;
import javafx.application.Application;
import javafx.beans.property.DoubleProperty;
import javafx.beans.property.SimpleDoubleProperty;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.Label;
import javafx.scene.control.ProgressBar;
import javafx.scene.layout.Pane;
import javafx.scene.layout.VBox;
import javafx.scene.paint.Color;
import javafx.scene.shape.Rectangle;
import javafx.stage.Stage;
import javafx.util.Duration;
public class TwoColoredRectangle extends Application {
@Override
public void start(Stage primaryStage) {
// property to change:
DoubleProperty life = new SimpleDoubleProperty(100);
// "animate" the property for demo:
Timeline timeline = new Timeline(
new KeyFrame(Duration.ZERO, new KeyValue(life, 100)),
new KeyFrame(Duration.seconds(2), new KeyValue(life, 0))
);
// button to set the animation going:
Button startButton = new Button("Start");
startButton.setOnAction(e -> timeline.playFromStart());
VBox root = new VBox(5);
// Solution 1. One rectangle on another:
Rectangle base = new Rectangle(0, 0, 400, 20);
base.setFill(Color.GRAY);
Rectangle lifeRect = new Rectangle(0, 0, 400, 20);
lifeRect.setFill(Color.GREEN);
lifeRect.widthProperty().bind(life.multiply(4));
Pane solutionPane1 = new Pane(base, lifeRect);
root.getChildren().add(createSolutionPane("Dynamic rectangle on fixed rectangle", solutionPane1));
// Solution 2: Two rectangles changing together:
Rectangle leftRect = new Rectangle();
leftRect.setHeight(20);
leftRect.setFill(Color.GREEN);
Rectangle rightRect = new Rectangle();
rightRect.setHeight(20);
rightRect.setFill(Color.GRAY);
leftRect.widthProperty().bind(life.multiply(4));
rightRect.xProperty().bind(leftRect.widthProperty());
rightRect.widthProperty().bind(life.multiply(-4).add(400));
Pane solutionPane2 = new Pane(leftRect, rightRect);
root.getChildren().add(createSolutionPane("Two dynamic rectangles", solutionPane2));
// Solution 3: Green rectangle on gray-styled pane:
Pane basePane = new Pane();
basePane.setMinSize(400, 20);
basePane.setMaxSize(400, 20);
// gray color will be defined in CSS:
basePane.getStyleClass().add("base-pane");
Rectangle rect = new Rectangle();
rect.setHeight(20);
rect.setFill(Color.GREEN);
rect.widthProperty().bind(life.multiply(4));
basePane.getChildren().add(rect);
root.getChildren().add(createSolutionPane("Dynamic rectangle on pane", basePane));
// Solution 4: Dynamically-styled pane:
Pane dynamicPane = new Pane();
dynamicPane.setMinSize(400, 20);
dynamicPane.setMaxSize(400, 20);
dynamicPane.getStyleClass().add("dynamic-pane");
// make background insets depend on the property:
dynamicPane.styleProperty().bind(life.multiply(4).asString("-fx-background-insets: 0, 0 0 0 %f"));
root.getChildren().add(createSolutionPane("Dynamically styled pane", dynamicPane));
// Solution 5: Progress bar:
ProgressBar progressBar = new ProgressBar();
progressBar.setPrefSize(400, 20);
progressBar.progressProperty().bind(life.divide(100));
root.getChildren().add(createSolutionPane("Progress bar", progressBar));
root.getChildren().add(startButton);
Scene scene = new Scene(root);
scene.getStylesheets().add("two-colored-rectangle.css");
primaryStage.setScene(scene);
primaryStage.show();
}
private Node createSolutionPane(String title, Node content) {
VBox vbox = new VBox(new Label(title), content);
vbox.getStyleClass().add("solution-pane");
return vbox ;
}
public static void main(String[] args) {
launch(args);
}
}
and the stylesheet (two-colored-rectangle.css
):
.root {
-fx-padding: 20 ;
-fx-alignment: center ;
}
.base-pane {
-fx-background-color: gray ;
}
.dynamic-pane {
-fx-background-color: green, gray ;
}
.solution-pane {
-fx-spacing: 5 ;
-fx-padding: 10 ;
}
.progress-bar {
-fx-accent: green ;
-fx-control-inner-background: gray ;
}
Upvotes: 4
Reputation: 13
From your problem statement, I believe the literal answer to your question above would have to be "No", you cannot fill the background of a rectangle with two different colors. It must be one or the other.
But to achieve the goal implicit in your question, (from James_D's comment) You could paint one rectangle in your first color, and progressively cover it with a second rectangle. Or you could paint two separate rectangles, each with a different color, each with a width that would together fill the entire bar. So at first, the rightmost rectangle would fill the bar 100% and the leftmost rectangle would be 0%. Then the size of each would change, the right to 99% and the left to 1%. And so on.
Upvotes: 1