John
John

Reputation: 952

Check a value from the database

I am trying to get a value from the database. If this value is equal to 1, it needs to show the text "One".

But my script is not working. To check if the result of the sql statement is equal to 1 i am using the following part:

if ($result==1)

    {
        echo 'One'; 
    }

But this is the result I get:

else
    {
    echo 'None';
    }

I think that $result==1 is not representing a integer.

Does anybody know how I can make this script working?

Here is other part of my script:

<?php

$user_name = "root";
$password = "";
$database = "db";
$server = "localhost";

$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);

if ($db_found) {
$result =mysql_query("SELECT id FROM users WHERE user_id=1");
if ($result==1)

    {
        echo 'One'; 
    }

if ($result==2)

    {
        echo 'Two'; 
    }

if ($result==3)

    {
        echo 'Three'; 
    }

else
    {
    echo 'None';
    }
}
else {
print "Database NOT Found.";
mysql_close($db_handle);
}
?>

Upvotes: 0

Views: 66

Answers (2)

Passionate Coder
Passionate Coder

Reputation: 7294

Please try this.

  <?php

    $user_name = "root";
    $password = "";
    $database = "db";
    $server = "localhost";

    $db_handle = mysql_connect($server, $user_name, $password);
    $db_found = mysql_select_db($database, $db_handle);

    if ($db_found) {
    $result =mysql_query("SELECT id FROM user WHERE user_id = 1");
    $result = mysql_fetch_array($result);}
    if($result){
        echo $result['id'];

    }
    else
        {
        echo 'None';
        }

    mysql_close($db_handle);
    ?>

Upvotes: 0

chandresh_cool
chandresh_cool

Reputation: 11830

Change to this :

$result =mysql_query("SELECT id FROM users WHERE user_id=1");
$count = mysql_num_rows($result);

if ($count == 1) {
    echo 'One'; 
}

and so on

Note :- The mysql extension is deprecated and will be removed in the future: use mysqli or PDO instead

If you want exact value from sql, use below code :

$res = mysql_fetch_row($result);

if ($res[0] == 1) {
    echo 'One'; 
}

Upvotes: 1

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