CODEWITHSUNDEEP
javascriptarrays
user5372593
user5372593

Reputation:

Checking multiple array elements in if statement

I'm writing a simple tic tac toe game, and I'm trying to check for different win states. The different tiles are set up in an array, so to check for a win for the three top spaces I have

if (tableArr[0].hasClass('userTaken') && tableArr[1].hasClass('userTaken') && tableArr[2].hasClass('userTaken')){
    select(); //ends game
}

I'm looking for a way to shorten this, I tried tableArr[0,1,2].hasClass('userTaken') but that didn't work. Any suggestions?

Upvotes: 0

Views: 209

Answers (2)

Jose Hermosilla Rodrigo
Jose Hermosilla Rodrigo

Reputation: 3683

Also you could check if some element doesn't have the class with some : 

tableArr.slice(0, 3).some(x => !x.hasClass('userTaken'))

Upvotes: 0

slugonamission
slugonamission

Reputation: 9642

You could potentially use every for this, but you'd also need to slice the array too. As an example:

tableArr.slice(0, 3).every(x => x.hasClass('userTaken'))

So, take the first three elements of the array using slice, then every checks that the test passes for each of them.

Of course, if this is tic, tac, toe, you'll need to check diagonals too, which is trickier using .slice. You could use map for this too, e.g.

[0,1,2].map(idx => tableArr[idx]).every(x => x.hasClass('userTaken'))

Upvotes: 3

Related Questions