Reputation: 351
Hi all I am trying to build a quiz application using angular JS, I am having two tables Questions and Answers and the code is as follows
public class Question
{
public int QuestionID { get; set; }
public string QuestionName { get; set; }
public List<Options> Options = new List<Options>();
}
public class Options
{
public int AnswerId { get; set; }
public int QuestionID { get; set; }
public string Answer { get; set; }
public bool isAnswer { get; set; }
}
public static class QuizDetails
{
public static string GetQuiz()
{
Dictionary<int, List<Question>> displayQuestion = new Dictionary<int, List<Question>>();
//List<Quiz> quiz = new List<Quiz>();
//Options op1 = new Options();
dbDataContext db = new dbDataContext();
var v = (from op in db.QUESTIONs
join pg in db.ANSWERs on op.QUESTION_ID equals pg.QUESTION_ID
select new { Id = op.QUESTION_ID, Name = op.QUESTION_NAME, pg.ANSWER_ID, pg.QUESTION_ID, pg.ANSWER_DESCRIPTION, pg.CORRECT_ANSWER }).ToList();
return JsonConvert.SerializeObject(v);
}
}
This is my reference code for building the application http://www.codeproject.com/Articles/860024/Quiz-Application-in-AngularJs, how can I return the JSON format as per the code written in the JS files can some one help me
Upvotes: 0
Views: 82
Reputation: 38490
Right now GetQuiz
returns a string that represents an object. Your client doesn't really know what the string contains, it just handles it as a normal string.
You can either return it in another way, for example:
return new HttpResponseMessage
{
Content = new StringContent(
JsonConvert.SerializeObject(v),
System.Text.Encoding.UTF8,
"application/json")
};
If you want to keep returning it as a string you will have to manually deserialize it in the client:
var object = angular.fromJson(returnedData);
Upvotes: 1