CODEWITHSUNDEEP
pythonhttpheaderresponse
Naomi
Naomi

Reputation: 311

How to print out http-response header in Python

Today I actually needed to retrieve data from the http-header response. But since I've never done it before and also there is not much you can find on Google about this. I decided to ask my question here.

So actual question: How does one print the http-header response data in python? I'm working in Python3.5 with the requests module and have yet to find a way to do this.

Upvotes: 33

Views: 108841

Answers (8)

Ahmed
Ahmed

Reputation: 464

easy

import requests

site = "https://www.google.com"
headers = requests.get(site).headers
print(headers)

if you want something specific

print(headers["domain"])

Upvotes: 7

Kevin Liu
Kevin Liu

Reputation: 737

I'm using the urllib module, with the following code:

from urllib import request
with request.urlopen(url, data) as f:
    print(f.getcode())  # http response code
    print(f.info())     # all header info

    resp_body = f.read().decode('utf-8') # response body

Upvotes: 4

Josh Correia
Josh Correia

Reputation: 4346

Here's how you get just the response headers using the requests library like you mentioned (implementation in Python3):

import requests

url = "https://www.google.com"
response = requests.head(url)
print(response.headers) # prints the entire header as a dictionary
print(response.headers["Content-Length"]) # prints a specific section of the dictionary

It's important to use .head() instead of .get() otherwise you will retrieve the whole file/page like the rest of the answers mentioned.

If you wish to retrieve a URL that requires authentication you can replace the above response with this:

response = requests.head(url, auth=requests.auth.HTTPBasicAuth(username, password))

Upvotes: 14

Brian Gicharu
Brian Gicharu

Reputation: 57

import pprint
import requests

res = requests.request("GET", "https://google.com")

pprint.PrettyPrinter(indent=2).pprint(dict(res.headers))

Upvotes: 1

mohamed abdelwahab
mohamed abdelwahab

Reputation: 37

its very easy u can type

print(response.headers)

or my fav

print(requests.get('url').headers)
also u can use

print(requests.get('url').content)

Upvotes: 2

Utkarsh Agrawal
Utkarsh Agrawal

Reputation: 87

Try to use req.headers and that's all. You will get the response headers ;)

Upvotes: 0

Dilettant
Dilettant

Reputation: 3335

Update: Based on comment of OP, that only the response headers are needed. Even more easy as written in below documentation of Requests module:

We can view the server's response headers using a Python dictionary:

>>> r.headers
{
    'content-encoding': 'gzip',
    'transfer-encoding': 'chunked',
    'connection': 'close',
    'server': 'nginx/1.0.4',
    'x-runtime': '148ms',
    'etag': '"e1ca502697e5c9317743dc078f67693f"',
    'content-type': 'application/json'
}

And especially the documentation notes:

The dictionary is special, though: it's made just for HTTP headers. According to RFC 7230, HTTP Header names are case-insensitive.

So, we can access the headers using any capitalization we want:

and goes on to explain even more cleverness concerning RFC compliance.

The Requests documentation states:

Using Response.iter_content will handle a lot of what you would otherwise have to handle when using Response.raw directly. When streaming a download, the above is the preferred and recommended way to retrieve the content.

It offers as example:

>>> r = requests.get('https://api.github.com/events', stream=True)
>>> r.raw
<requests.packages.urllib3.response.HTTPResponse object at 0x101194810>
>>> r.raw.read(10)
'\x1f\x8b\x08\x00\x00\x00\x00\x00\x00\x03'

But also offers advice on how to do it in practice by redirecting to a file etc. and using a different method:

Using Response.iter_content will handle a lot of what you would otherwise have to handle when using Response.raw directly

Upvotes: 24

NepCoder
NepCoder

Reputation: 439

How about something like this:

import urllib2
req = urllib2.Request('http://www.google.com/')
res = urllib2.urlopen(req)
print res.info()
res.close();

If you are looking for something specific in the header:

For Date: print res.info().get('Date')

Upvotes: 11

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