John
John

Reputation: 151

ElementTree element index look up

I'm using the xml.etree.ElementTree module to create an XML document with Python 3.1 from another structured document.

What ElementTree function can I use that returns the index of an existing sub element?

Upvotes: 15

Views: 20090

Answers (3)

user2160906
user2160906

Reputation: 5

def alarms_validation(self, path, alarm_no, alarm_text):
    with open(path) as f:
        tree = et.parse(f)
        root = tree.getroot()
        try:
            for x in xrange(10000):
                print x
                for y in xrange(6):
                    print y
                    if root[x][y].text == alarm_no:
                        print "found"
                        if root[x][y+1].text != alarm_text:
                            print "Alarm text is not proper"
                        else:
                            print "Alarm Text is proper"
        except IndexError:
            pass

Upvotes: -2

user2160906
user2160906

Reputation: 5

import xml.etree.ElementTree as ET
root=ET.Element('C:\Users\Administrator\Desktop\ValidationToolKit_15.9\ValidationToolKit_15.9\NE3S_VTK\webservice\history\ofas.2017-1-3.10-55-21-608.xml')
childnew=ET.SubElement(root,"354")
root.getchildren().index(childnew)
0
list(root).index(childnew)
0

Upvotes: 0

Mark
Mark

Reputation: 108537

The getchildren method returns a list of sub-elements of an Element object. You could then use the built-in index method of a list.

>>> import xml.etree.ElementTree as ET
>>> root = ET.Element("html")
>>> head = ET.SubElement(root, "head")
>>> body = ET.SubElement(root, "body")
>>> root.getchildren().index(body)
1

Upvotes: 13

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