CODEWITHSUNDEEP
javascript
Luntegg
Luntegg

Reputation: 2556

A function in JS with parameter passing

It's the test task on the job.

A farmer has rabbits. Each rabbit is its weight. When the time comes, he kills them function cut(rabbit). You must write a function of cut so that it had the appearance of cut(rabbit1)(rabbit2)...(rabbitN) and deduced the total mass and the number of rabbits.

For example:

var rabbit1 = {weight: 5},
    rabbit2 = {weight: 4};

console.log(cut(rabbit1)(rabbit2));

In the console we will see "9 kg of rabbits or 2 pieces".

JSFiddle - https://jsfiddle.net/sjao7ut8/

How I can write function cut()?

Upvotes: 4

Views: 118

Answers (4)

Oshadha
Oshadha

Reputation: 548

You can try following code:

var farmer = { 
    cut: function(rabits) { 
    var cutWeight = 10;
    var totalCuts = 0;
    var totalWeight = 0;
    var count = rabits.length;

    for(var i=0; i < count; i++) {
        var rabit = rabits[i];

      if(rabit.weight >= cutWeight) {
        totalWeight += rabit.weight;
        if(totalCuts === 0) {
            totalCuts = 1;
        }
        else {
            totalCuts += 1;
        }
      }
    }

    console.log(totalWeight + "Kg of Rabits and " + totalCuts + "cuts.")
  }
};

farmer.cut([{weight: 11}, {weight: 5}, {weight: 13}]); // Call the function

Hope this will help you.

Upvotes: 0

Ivan Pomortsev
Ivan Pomortsev

Reputation: 238

Function.prototype.toString = function() {
 return Function.prototype.rabbitsWeight + "кг кроликов или " + Function.prototype.rabbitsCount + " штук";
}; 

Function.prototype.rabbitsWeight = 0;
Function.prototype.rabbitsCount = 0;

window.rabbitsCut = eval("new Function('rabbit', 'Function.prototype.rabbitsWeight += rabbit.weight; ++Function.prototype.rabbitsCount; return eval(window.rabbitsCut);');");

var cut = window.rabbitsCut;

console.log(cut({weight: 5})({weight: 4}));

Upvotes: -1

Nina Scholz
Nina Scholz

Reputation: 386766

You could use chaining, a fluent interface, which returns the function you called until the environment requires a primitive value.

function cut(rabbit) {
    var weight = 0,
        count = 0,
        fn = function (o) {
            weight += o.weight;
            count++;
            return fn;
        };

    fn.toString = function () {
        return weight + ' kg of rabbits or ' + count + ' piece' + (count > 1 ? 's' : '');
    }

    return fn(rabbit);
}

var rabbit1 = { weight: 5 },
    rabbit2 = { weight: 4 };
    
console.log(cut(rabbit1)(rabbit2));

Upvotes: 7

pwolaq
pwolaq

Reputation: 6381

what you need to do here is to use recursive call, which returns a function and uses arguments.callee

something like this should do the job:

function cut(firstRabbit) {
    var mass = firstRabbit.weight;
    return function(nextRabbit) {
        if (typeof nextRabbit !== 'undefined') {
            mass += nextRabbit.weight;
            return arguments.callee;
        } else {
            return mass;
        }
    };
}

Example usage (remember to add () at the end):

var rabbit1 = {weight: 5},
rabbit2 = {weight: 4};

console.log(cut(rabbit1)(rabbit2)());

Upvotes: 0

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