CODEWITHSUNDEEP
pythonsplit
radicaled
radicaled

Reputation: 2699

Split file name on python

I'm trying to split a filename use it by parts.
The file is always an apache binary (for example, httpd-2.2.31.tar.gz) and I only need the version (in this case 22) in that specific format.
I have done it and it works, but I believe there should be a better way

binary_name = "httpd-2.2.31.tar.gz"
app, ver_tar = binary_name.split("-")
version = ver_tar.split(".")
print ("Version %s%s" % (version[0], version[1]))

Is it possible to do it in a better way?

Upvotes: 0

Views: 162

Answers (4)

TheLazyScripter
TheLazyScripter

Reputation: 2665

As far as a better way there is no such thing as long as your code solves the problem you set out to solve, and in this case it does. As far as performance goes there are probably faster ways to achieve the same thing but even with a list of thousands of string to parse the difference in speed would be minimal or indistinguishable. Therefore I assume you are instead asking for a different way to accomplish the same goal, so I have written a small function and several test segments. The function gives slightly more control.

def get_version(file_name, accuracy=0, sep=None):
    '''
        :string file_name is the string you want to parse
        :int accuracy is the length of the output format 
            1 = 1 of 1.23.3
            2 = 1.2 of 1.23.3
            3 = 1.23 of 1.23.3
            0 = 1.23.3 or full length
        :string sep, is the string seperator you wish to use, 1.1, 1_1, 11 etc...
        '''

    if not sep:
        sep = ''
    data = file_name.split('.')
    str_ver = data[0:-2]
    ver = []
    for i in str_ver:
        if len(ver) < accuracy or accuracy == 0:
            try:
                if len(i)>1:
                    n = ''
                    for x in i:
                        try:
                            n+=str(int(x))
                        except:
                            pass
                else:
                    n = str(int(i))
                ver.append(n)
            except:
                pass
    return sep.join(ver)

print get_version("httpd-2.2.31.tar.gz", 1, '--')
print get_version("httpd-2.2.31.tar.gz", 2, '::')
print get_version("httpd-2.2.31.tar.gz", 3, '_')
print get_version("httpd-2.2.31.tar.gz", 2)#what you were asking for
print get_version("httpd-2.2.31.tar.gz")

Upvotes: 0

vks
vks

Reputation: 67988

use re

(?<=-)(\d+)\.(\d+)

See demo.

Regex101 demo

or

Pythex demo

import re
x= "httpd-2.2.31.tar.gz"
print re.findall(r"(?<=-)(\d+)\.(\d+)", x)

Upvotes: 2

gr1zzly be4r
gr1zzly be4r

Reputation: 2162

You could make it a little easier by using regular expressions. There's a nifty site called Pythex where you can experiment with these yourself. To fix your example:

import re
r = re.compile(".*-(\d+\.\d+\.\d+).tar.gz")
print(r.match("httpd-2.2.21.tar.gz").groups()[0])

Upvotes: 0

aroy
aroy

Reputation: 482

if you want to do it in one line,may be it will help :

binary_name = "httpd-2.2.31.tar.gz"
print binary_name.split("-")[1][:3].replace('.','')

will return 22

Upvotes: 1

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