CODEWITHSUNDEEP
c#file
Yeep
Yeep

Reputation: 43

Stream read file, and create dynamic byte

I hit this error

The process cannot access because it is being used by another process.

The error show at var br = new BinaryReader(new FileStream(fileName, FileMode.Open));

I trying to do this because i want the byte to be dynamic. 

    foreach (string dir in dirs)
            {

                string fileName = Path.GetFileName(dir);


                using (Stream source = System.IO.File.OpenRead(dir))
                {
                    byte[] buffer;
                    var br = new BinaryReader(new FileStream(fileName, FileMode.Open));
                    buffer = br.ReadBytes((int)br.BaseStream.Length);

                }
}

Upvotes: 1

Views: 1124

Answers (2)

Arion
Arion

Reputation: 31239

Can't you just do this:

using (var source = new FileStream(dir, FileMode.Open))
{
     byte[] buffer;
     var br = new BinaryReader(source);
     buffer = br.ReadBytes((int)br.BaseStream.Length);
}

Alternative you can do this:

File.ReadAllBytes(dir);

Upvotes: 1

Alexander Petrov
Alexander Petrov

Reputation: 14231

Here you open the file at first time:

System.IO.File.OpenRead(dir)

Here you are trying to open the same file second time:

new FileStream(fileName, FileMode.Open)

Of course that file is already occupied.


Rewrite the code as follows:

using (var source = File.OpenRead(dir))
using (var br = new BinaryReader(source))
{
    byte[] buffer = br.ReadBytes((int)br.BaseStream.Length);
}

Upvotes: 1

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