CODEWITHSUNDEEP
stringswift
Cue
Cue

Reputation: 3092

How can I create a list of words that contains upper case letters in swift?

I would like to generate a list of words form a given string where each listed word contains at least an upper case letter.

Having a string like this one:

let str: String = "Apple watchOS 3 USA release date and feature rumours."

I would like to get an array like this:

var list: [String] = ["Apple", "watchOS", "USA"]

What is the best way to do this?

Upvotes: 4

Views: 315

Answers (3)

Duyen-Hoa
Duyen-Hoa

Reputation: 15784

You can use built in function of String in Swift that get all words of a string. It's better than just separate by a space (" ") cause you can have some words with a point (like the example below)

let str = "Apple watchOS 3 USA release date and feature Rumours."
var list = [String]()
str.enumerateSubstringsInRange(str.startIndex..<str.endIndex, options:.ByWords) { 
    (substring, substringRange, enclosingRange, value) in
    //add to your array if lowercase != string original
    if let _subString = substring where _subString.lowercaseString != _subString {
        list.append(_subString)
    }
}

Upvotes: 3

AtheistP3ace
AtheistP3ace

Reputation: 9691

You can probably do something like this. I haven't tested it, just wrote it real quick.

let str = "Apple watchOS 3 USA release date and feature rumours."
let strArr = str.componentsSeparatedByString(" ")
var upperWords: Array<String> = []
for word in strArr {
    if word != word.lowercaseString {
        upperWords.append(word)
    }
}

Upvotes: 0

NSGangster
NSGangster

Reputation: 2447

var list = str.componentsSeparatedByString(" ").filter{ $0.lowercaseString != $0 }

Upvotes: 12

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