CODEWITHSUNDEEP
c++segmentation-fault
dlpsankhla
dlpsankhla

Reputation: 152

Why segmentation fault in the following code?

This is my code: 

char * name[]={"Dileep","Avina"};
name[0][1]='A';

here name[0] is an char* pointing to string literal "Dileep". So what will be the name[0][1]? Why it is giving me runtime error?

Upvotes: 0

Views: 56

Answers (2)

songyuanyao
songyuanyao

Reputation: 172914

name[0] is an char* pointing to string literal "Dileep".

No, char * name[] is spurious. "Dileep" is string literal with type const char[7], and your code is not allowed since C++11 because of the conversion from string literal to char *. char * name[]={"Dileep","Avina"}; should be const char * name[]={"Dileep","Avina"};.

So what will be the name[0][1]?

It should be a const char.

Why it is giving me runtime error?

Modifying string literal is UB.

Upvotes: 0

Mark Tolonen
Mark Tolonen

Reputation: 177610

"Dileep" and "Avina" are string constants. Trying to change them is undefined behavior. If the OS puts them in read-only memory, you will get a fault.

Upvotes: 3

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