CODEWITHSUNDEEP
javascriptregex
bflemi3
bflemi3

Reputation: 6790

Capture group certain number of times with regular expression but last group has remaining values

Given a string delimited by a colon and similar to this...

xvf:metric:admin:click

I need to capture three groups...

xvf
metric
admin:click

Or another example:

one:two:three:four:five:six:seven

one
two
three:four:five:six:seven

My current regex is just capturing each word separately, resulting in 4 matches

/(\s*\w+)/gi

Upvotes: 0

Views: 55

Answers (4)

YakovL
YakovL

Reputation: 8345

And if it's possible that you get less than 3 groups, you can use

/^([^:]+)(?::([^:]+)(?::(.+)?)?)?$/

You can find an "explanation" of the RegExp here.

Upvotes: 1

hjpotter92
hjpotter92

Reputation: 80649

Since you're using JavaScript, it'd make more sense to actually use string.split and later Array.slice and Array.splice for string manipulation:

var str = "one:two:three:four:five:six:seven",
  groups = str.split(':');
groups.splice(2, groups.length, groups.slice(2).join(':'));
console.log(groups);

Upvotes: 0

RomanPerekhrest
RomanPerekhrest

Reputation: 92884

The solution using String.match and Array.slice functions:

var str = "one:two:three:four:five:six:seven",
    groups = str.match(/([^:]+?):([^:]+?):(.+)?$/).slice(1);

console.log(groups);  // ["one", "two", "three:four:five:six:seven"]

Upvotes: 1

Keatinge
Keatinge

Reputation: 4321

The solution is to capture the first two things before a :, then capture everything after

Here's the regex:

/(.+?):(.+?):(.+)/

In code:

var testStr = "xvf:metric:admin:click";

console.log(/(.+?):(.+?):(.+)/.exec(testStr).slice(1,4))
//["xvf", "metric", "admin:click"]

Upvotes: 0

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