Reputation: 4603
<div class="addMore">
<div class="row addPlus">
<p class="emergencyTitle">Child 1</p>
<div class="col-xs-6">
<form role="form">
<div class="form-group">
<label for="name">Student Name</label>
<input type="text" class="form-control" name="ch1_name">
</div>
<div class="form-group">
<label for="name">Class</label><br>
<select name="ch1_class">
<option value=""> 1 </option>
<option value=""> 2</option>
<option value=""> 3 </option>
</select>
</div>
</form>
</div>
<div class="col-xs-6">
<form role="form">
<div class="form-group">
<label for="name">DOB</label>
<input type="text" class="form-control" name="ch1_dob" id="datepicker">
</div>
<div class="form-group">
<label for="name">Section</label><br>
<select name="ch1_secion">
<option value=""> A </option>
<option value=""> B </option>
<option value=""> C </option>
</select>
</div>
</form>
</div>
</div>
</div>
On the click of a button I am doing this ..
$child = $('.addPlus')
$('.addMore').append($child)
But I cannot seem to add the addPlus div, how over $('.addMore').append("hi")
works fine. Can anyone help me out where I am going wrong.
Upvotes: 1
Views: 74
Reputation: 337637
.addPlus
is already appended to .addMore
, so your jQuery would work but have no effect.
Assuming you want to copy the existing instance of .addPlus
you should call clone()
on it before appending it to the parent, like this:
var $newChild = $('.addPlus').first().clone()
$('.addMore').append($newChild)
Upvotes: 0
Reputation: 1011
if you want to clone the item - you can use
$('.addPlus').first().clone().appendTo('.addMore')
Upvotes: 2