Reputation: 453
One of my friends asked me why simple equivalent formulas get different results. Excuse me that the code is a bit long but the interesting part is just line 99 and 100. Here is the formulas and the code.
I checked the code. The problem is where f = 1
.
The problem is line 99 and 100. It takes about 10 s to run the code.
Thanks for any guide or comment.
Upvotes: 0
Views: 59
Reputation: 281
Simple. It is just because of round off errors. What you have commented out has some round off errors which makes fplus~=1
, so:
E = log( (1 - 1") / 1) >= log(eps) >= -36.0437.
while the real value should be:
E = log( (1 - 1) / 1) = log(0) = -Inf
Upvotes: 1