Reputation: 43
if(true) {
tmp = 'abc';
console.log(tmp);//which should throw referenceError but not
let tmp;
console.log(tmp);
tmp = 123;
console.log(tmp);
}
This code results in
abc
undefined
123
Why does the first console.log(tmp) not throw an error?
In ECMAScript 2015, let will hoist the variable to the top of the block. However, referencing the variable in the block before the variable declaration results in a ReferenceError. The variable is in a "temporal dead zone" from the start of the block until the declaration is processed.
Upvotes: 2
Views: 266
Reputation: 664336
You are correct, in ES6 this does throw an exception. There's two reasons why it doesn't for you:
let
- but it works correctly only in strict mode. You should use it.es6.blockScopingTDZ
/es6.spec.blockScoping
option (but I'm not sure whether this worked in Babel 5 only and what happened in Babel 6 to them).Upvotes: 2
Reputation: 803
Statement
tmp = 'abc';
is not elegant but still OK in normal mode (except let keyword which is not allowed outside strict mode). It will simply create global variable. However, the code is not correct and will throw an error only when you executed this code in "strict mode". In this mode you have to declare all variables with one of this keywords:
'use strict'
if(true) {
tmp = 'abc';
console.log(tmp);//which should throw referenceError and now it does
let tmp;
console.log(tmp);
tmp = 123;
console.log(tmp);
}
Upvotes: 0
Reputation: 385104
No, it shouldn't throw a reference error.
The variable is implicitly declared (in the global scope) when you assign to it.
Then, later, you declare a new variable with the same name but a tighter scope. The new variable is not hoisted because it is declared using let
.
I can't give a more precise answer, because you did not explain why you think you should get a reference error.
Upvotes: -2