Reputation:
I have the following code which gets the date parsed, the subtracts 1 month. This works perfectly.
$date = '22-05-2016';
print(date("Y-m-d 23:59:59", strtotime($date.' -1 months')));
// outputs 2016-04-22 23:59:59
There are times where I need to force the date to month end. For this I use Y-m-t
instead of Y-m-d
Which works perfectly.
$date = '22-05-2016';
print(date("Y-m-t 23:59:59", strtotime($date.' -1 months')));
// outputs 2016-04-30 23:59:59
$date = '31-05-2016';
print(date("Y-m-t 23:59:59", strtotime($date.' -1 months')));
Actual Output 2016-05-31 23:59:59 (hasn't removed 1 month)
Desired Output 2016-04-30 23:59:59
EDIT: Fiddle example http://ideone.com/0fqlor
Upvotes: 1
Views: 474
Reputation: 3795
Try:
$date = '31-05-2016';
print(date("Y-m-d 23:59:59", strtotime($date.' last day of last month')));
and dig into strtotime
possibilities ;)
Take a look here: http://php.net/manual/en/datetime.formats.relative.php
Last Note: -1 month
only gets 30 days back in time. Therefore it will not work allways. Some kind of PHP stuff, i think ;)
Upvotes: 2
Reputation: 20899
strtotime
is your friend. The last day of any "given" month can be retrieved using the verbal String last day of May 2015
- so, for easy input (guess you have a date-picker not a month-picker), convert the selected date to its month expression first:
date_default_timezone_set('Europe/London');
$to = '31-05-2016';
$month = date("M Y", strtotime($to));
$strtotime_expression = "last day of " . $month;
echo $strtotime_expression.": <br />";
print(date("Y-m-t 23:59:59", strtotime($strtotime_expression)));
Upvotes: 0