CODEWITHSUNDEEP
javascriptunit-testingjasminefirebase-realtime-databasespyon
1dolinski
1dolinski

Reputation: 549

Mocking a firebase calls using Jasmine

I'm looking to spyOn calls to the firebase database. I have a FireFunc file that wraps firebase calls. However, when I go to spyOn the check method, it returns the regular result. What's going on here?

var FireFunc = require("../js/services-fb-functions.js");

describe('Firebase Testing Suite', function() {
    var firebase;
    var testPath;
    var testResult = {};

    beforeAll(function() {
        var firebaseFunctions = ['check']
        firebase = jasmine.createSpyObj('firebase', firebaseFunctions)

        firebase.check.and.callFake(function() {
            return 2
        });
   });

   describe('check', function() {
    it('is working?', function() {
        var x = FireFunc.zset()
        expect(x).toBe(3); // THIS IS RETURNING 1... which means the spyOn doesn't work for me !
    });
});

This is my code (js/services-fb-functions.js)

var firebase = {};
firebase.check = function() {
    return 1;
}

module.exports = {
    zset: function() {
        return firebase.check();
    }
}

Upvotes: 1

Views: 1351

Answers (1)

dkichler
dkichler

Reputation: 317

The issue is that you have not supplied the mocked version of the firebase object to your object under test. The firebase object as it exists in js/services-fb-functions.js is purely internal is not exposed in any way for testing. Good practice would generally be to use dependency injection for providing internal objects that you wish to mock out during tests. I've adapted your code slightly to work with JSFiddle and Jasmine 1.3, so please excuse my limited JS skills (there are definitely more elegant ways of exposing the internal object), but this JSFiddle should demonstrate my point: Simple Jasmine example using spies

Upvotes: 1

Related Questions