Reputation: 1093
In my Oracle database there are two tables which are TEMP_HR and PAY_SLIP_APR_16. Both of them have a common column named EMP_ID. TEMP_HR has over 10,000 records and PAY_SLIP_APR_16 has around 6,000 records. I want to know how many EMP_ID of PAY_SLIP_APR_16 is matched with TEMP_HR. If any ID doesn't match then print it. And here is my simple approach but I think its a very bad approach. So any faster method?
DECLARE
INPUT_EMP_NO VARCHAR2(13 BYTE);
INPUT_EMP_ID VARCHAR2(13 BYTE);
ROW_COUNT_1 NUMBER(6,0);
ROW_COUNT_2 NUMBER(6,0);
MATCHED_ID NUMBER;
UNMATCHED_ID NUMBER;
BEGIN
ROW_COUNT_1:=0;
ROW_COUNT_2:=0;
MATCHED_ID:=0;
UNMATCHED_ID:=0;
SELECT COUNT(*) INTO ROW_COUNT_1 FROM PAY_SLIP_APR_16;
SELECT COUNT(*) INTO ROW_COUNT_2 FROM TEMP_HR;
FOR A IN 1..ROW_COUNT_1 LOOP
BEGIN
SELECT EMP_ID INTO INPUT_EMP_ID FROM (SELECT EMP_ID, ROWNUM AS RN FROM PAY_SLIP_APR_16) WHERE RN=A;
FOR B IN 1..ROW_COUNT_2 LOOP
SELECT EMP_NO INTO INPUT_EMP_NO FROM (SELECT EMP_NO, ROWNUM AS RON FROM TEMP_HR) WHERE RON=B;
IF(INPUT_EMP_ID=INPUT_EMP_NO)THEN
MATCHED_ID:=MATCHED_ID+1;
EXIT;
ELSE
CONTINUE;
END IF;
END LOOP;
UNMATCHED_ID:=UNMATCHED_ID+1;
DBMS_OUTPUT.PUT_LINE(INPUT_EMP_ID);
EXCEPTION
WHEN OTHERS THEN
DBMS_OUTPUT.PUT_LINE(INPUT_EMP_ID||' -> '||SQLERRM);
END;
END LOOP;
DBMS_OUTPUT.PUT_LINE('MATCHED -> '||MATCHED_ID);
DBMS_OUTPUT.PUT_LINE('UNMATCHED -> '||UNMATCHED_ID);
END;
Upvotes: 1
Views: 37
Reputation: 425003
Use an outer join filtering for missed joins:
select p.*
from PAY_SLIP_APR_16 p
left join TEMP_HR t on t.EMP_ID = p.EMP_ID
where t.EMP_ID is null
An index on TEMP_HR(EMP_ID)
will make this query fly.
Upvotes: 2
Reputation: 8395
You should use SQL sets!
To check which EMP_ID
isn't in TEMP_HR
you may try this:
select EMP_ID FROM PAY_SLIP_APR_16
where EMP_ID not in (select EMP_NO from TEMP_HR);
Then the other way around:
select EMP_NO FROM TEMP_HR
where EMP_NO not in (select EMP_ID from PAY_SLIP_APR_16);
Upvotes: 0