akes406
akes406

Reputation: 531

Instagram URL --> JSON

How can I go about convering a public instagram URL into JSON using PHP? Ex: https://www.instagram.com/explore/tags/brindle/

I can't use the API as I need public hashtag content and my use case won't qualify for their app review process :-(.

Here is what I have so far but it does not pull all images. Also, I'd like to be able to load the "load more" images as well. Any help would be much appreciated!

$instagram_source = file_get_contents("https://www.instagram.com/explore/tags/brindle/");
$instagram_data = explode("window._sharedData = ", $instagram_source);
$instagram_json = explode(';</script>', $instagram_data[1]);
$instagram_array = json_decode($instagram_json[0], TRUE);

$instagram_media = $instagram_array['entry_data']['TagPage'][0]['tag']['media']['nodes'];
if(!empty($instagram_media)) {
echo '<ul>';
foreach($instagram_media as $im) {
echo '<li>';
    echo '<a href="https://www.instagram.com/p/'.$im['code'].'/" target="_blank">';
        echo '<img src="'.$im["display_src"].'" alt="" width="'.$im["dimensions"]["width"].'" height="'.$im["dimensions"]["height"].'" />';
    echo '</a>';
echo '</li>';
}
echo '</ul>';
}

Upvotes: 1

Views: 1260

Answers (1)

Pedro Casado
Pedro Casado

Reputation: 1745

Take a look at this solution here: https://github.com/Bolandish/Instagram-Grabber

Thats the best one i know until now.

Upvotes: 2

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