Reputation: 779
Here is my table table structure
id | Name | Date | VersionID
----+---------------+---------------+-------------------------------------
1 | Item 1 | 10/15/2012 | F8883CA4-3603-476D-BA33-1BBB6B87A79F
1 | Item 1 | 11/06/2012 | AA22DA27-87D1-42EC-96F6-A4846A45DF6B
1 | Item 1 | 11/06/2018 | AA22DA27-87D1-42EC-96F6-A4846A45DF6B
2 | Item 2 | 11/06/2015 | F8883CA4-3603-476D-BA33-1BBB6B87A79F
2 | Item 2 | 12/15/2012 | AA22DA27-87D1-42EC-96F6-A4846A45DF6B
2 | Item 2 | 1/19/2013 | F8883CA4-3603-476D-BA33-1BBB6B87A79F
From this table, for each version, I would like to get each item with max date.
Example
id | Name | Date | VersionID
----+---------------+---------------+-------------------------------------
1 | Item 1 | 10/15/2012 | F8883CA4-3603-476D-BA33-1BBB6B87A79F
1 | Item 1 | 11/06/2018 | AA22DA27-87D1-42EC-96F6-A4846A45DF6B
2 | Item 2 | 11/06/2015 | F8883CA4-3603-476D-BA33-1BBB6B87A79F
2 | Item 2 | 12/15/2012 | AA22DA27-87D1-42EC-96F6-A4846A45DF6B
I tried rank
and dense_rank
functions but the logic I tried isn't returning the expected results. Thoughts ?
Upvotes: 0
Views: 65
Reputation: 8865
We can get result by using MAX Condition and Co- related Subquery also
DECLARE @Table1 TABLE
(id int, Name varchar(6), Date datetime, VersionID varchar(36))
;
INSERT INTO @Table1
(id, Name, Date, VersionID)
VALUES
(1, 'Item 1', '2012-10-15 05:30:00', 'F8883CA4-3603-476D-BA33-1BBB6B87A79F'),
(1, 'Item 1', '2012-11-06 05:30:00', 'AA22DA27-87D1-42EC-96F6-A4846A45DF6B'),
(1, 'Item 1', '2018-11-06 05:30:00', 'AA22DA27-87D1-42EC-96F6-A4846A45DF6B'),
(2, 'Item 2', '2015-11-06 05:30:00', 'F8883CA4-3603-476D-BA33-1BBB6B87A79F'),
(2, 'Item 2', '2012-12-15 05:30:00', 'AA22DA27-87D1-42EC-96F6-A4846A45DF6B'),
(2, 'Item 2', '2013-01-19 05:30:00', 'F8883CA4-3603-476D-BA33-1BBB6B87A79F')
;
Select T.id,T.Name,TT.Dt,T.VersionID from @Table1 T
INNER JOIN (
select id,Name,MAX(Date)Dt,VersionID from @Table1
GROUP BY id,Name,VersionID)TT
ON T.id = TT.id AND T.Date = TT.Dt
Upvotes: 0
Reputation: 1269445
The normal way is to use row_number
:
select id, name, date, versionid
from (select s.*,
row_number() over (partition by id, version_id order by date desc) as seqnum
from structure s
) s
where seqnum = 1;
Upvotes: 3