CODEWITHSUNDEEP
winapi
Jonathan Weinraub
Jonathan Weinraub

Reputation: 387

How do I make a Win32 API button selected programatically?

I have a button, if i were to say click a checkbox, it should then give one of two buttons focus.

I am not sure how to use BM_SETSTATE - if that is the way to do it.

// snip...
    case WM_COMMAND:
    switch (LOWORD(wParam))
    {
    case IDC_CHECK:
        if (IsDlgButtonChecked(hDlg, IDC_CHECK))
        {
            EnableWindow(GetDlgItem(hDlg, IDOK), TRUE);
            EnableWindow(GetDlgItem(hDlg, IDCANCEL), TRUE);
            BM_SETSTATE // ... ?? 
        }
        else  
// ... snip

any help is greatly appreciated! thanks much!

Upvotes: 4

Views: 4141

Answers (2)

MOHW
MOHW

Reputation: 797

To make a button default in win32 (which i guess is your question) can simply be done by sending the button a BM_SETSTYLE message with BS_DEFPUSHBUTTON as the WPARAM...

HWND hwndButton = CreateWindow("button", "OK", WS_VISIBLE |...);

SendMessage(hwndButton, BM_SETSTYLE, (WPARAM)BS_DEFPUSHBUTTON, TRUE);

Hope this helps... ;-)

Upvotes: 2

Brian R. Bondy
Brian R. Bondy

Reputation: 347206

I'm not sure if you understand exactly what you're asking, but maybe.

The highlight state indicates whether the button is highlighted as if the user had pushed it. It does not indicate whether the button has focus nor does it indicate whether the button is checked or not.

If you really want to do this though, use the Button_SetState macro.

Just in case:

  • If you want to set the check state on a button use the Button_SetCheck macro.
  • If you want to set the focus on a button use the SetFocus Win32 API.
  • Note: Above I mentioned a couple macros, you can instead use SendMessage and pass the appropriate message as documented on the message in MSDN.

Upvotes: 4

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