CODEWITHSUNDEEP
python
Richard de Ree
Richard de Ree

Reputation: 2550

Multi dimensional array in Python

As noob in python I struggle with a multidimensional array I have this part 

def listMembers(Members):               
    for name in Names:
        age=Ages[name]
        print (name,age)

Names = ["John","William","Sarah"] 
Ages = [22,33,44]
Members=[Names,Ages]
listMembers(Members)

And expect as result: 

John, 22
Willem, 33
Sarah, 44

What must i change to get this?

Upvotes: 0

Views: 142

Answers (5)

hashcode55
hashcode55

Reputation: 5870

You can use enumerate to do the task... 

def listMembers():               
        for i,name in enumerate(Names):
            age=Ages[i]
            print (name,age)

Output - 

John 22
William 33
Sarah 44

But as said in the comments its better to use a dictionary here

Another way to do this is to use zip- 

def listMembers():               
    for i,j in zip(Names, Ages):
        print (i,j)

Edit :

As said in the comment you can do it without making direct references, as in real world, the function will be encapsulated within another class so you won't have direct access to data.- 

def listMembers(Members):
    names = Members[0]
    ages = Members[1]
    for i, j in zip(names, ages):
        print (i, ", ", j)

Upvotes: 2

Tom Karzes
Tom Karzes

Reputation: 24100

Here's the solution you're looking for. It gets all the information it needs from the Members argument, which may cointain any number of lists. The list elements are grouped, converted to strings, joined with ", ", and printed. There are no global references to Names or Ages:

def listMembers(Members):               
    for t in zip(*Members):
        print(", ".join(map(str, t)))

Names = ["John","William","Sarah"] 
Ages = [22,33,44]
Members=[Names,Ages]

listMembers(Members)

Here's the output:

John, 22
William, 33
Sarah, 44

Upvotes: 0

Alastair McCormack
Alastair McCormack

Reputation: 27744

The other answers show the cool in-built shortcuts in Python. However, IMHO you should really re-visit the basics the first and take the long route.

The following code uses basic functionality to create a list of integers ([0,1,2] in your case), which are iterated over to slice the arrays accordingly. This code assumes that names and ages has the same number of indexes.

def listMembers(Members):
    names = Members[0] # slice off the first dimension
    ages = Members[1] # slice off the first dimension

    names_len = len(names) # get the length of names 

    for i in xrange(names_len): # xrange builds a list from 0 to given length.
        print (names[i], ages[i]) # print off the second dimension


Names = ["John","William","Sarah"]
Ages = [22,33,44]
Members=[Names,Ages]
listMembers(Members)

Upvotes: 0

Joe T. Boka
Joe T. Boka

Reputation: 6581

You can use the the built-in function zip()

This will get you a list of tuples.

zipped = zip(Names, Ages)
tup_list = (list(zipped))
print (tup_list)
[('John', 22), ('William', 33), ('Sarah', 44)]

You can turn tup_list into a dictionary

dict(tup_list)
{'John': 22, 'Sarah': 44, 'William': 33}

Upvotes: 0

kardaj
kardaj

Reputation: 1935

You can use the zip built-in function:

Names = ["John", "William", "Sarah"]
Ages = [22, 33, 44]

for name, age in zip(Names, Ages):
    print name, ',', age

Upvotes: 1

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