CODEWITHSUNDEEP
pythonregexencoding
prashantgpt91
prashantgpt91

Reputation: 1795

Suppress 'u' in Output - Python

How can i get rid of these u in output?

Regex:

Tregex1 = "1?\W*([2-9][0-8][0-9])\W*([2-9][0-9]{2})\W*([0-9]{4})(\se?x?t?(\d*))?"

Code:

for a in re.findall(Tregex1,text_value,re.IGNORECASE):
        print a

Output:

(u'877', u'638', u'7848', u'\n', u'')
(u'650', u'627', u'1000', u'\n', u'')
(u'650', u'627', u'1001', u'\nE', u'')
(u'312', u'273', u'4100', u'', u'')

I tried using these & followed several similar links

a.encode('ascii', 'ignore')
a.encode('utf-8')
",".join(a)

But none of them are working.

Expected Output:

877-638-7848
650-627-1000
650-627-1001
312-273-4100

I am using Python 2.7

Also can someone explain, why i am getting sometimes \n while \nE otherwise or even blank?

Upvotes: 0

Views: 220

Answers (3)

phogl
phogl

Reputation: 504

try this:

for a in re.findall(Tregex1,text_value,re.IGNORECASE):
    print '-'.join(a[:3])

the u just tells you that it's a unicode string.

the (..., ...,) is the representation of the tuples

what '-'.join(...) does is connect the strings of ... with a -

a[:3] means "only the first three elements of a"

(for a good explanation of the slicing notation in python look here: https://stackoverflow.com/a/509295/327293)

Upvotes: 2

Dan
Dan

Reputation: 1227

The u just means it is unicode. You can recode it as you wish. This will work, and also skip the blank values:

a = (u'877', u'638', u'7848', u'\n', u'')
print "-".join([x.strip() for x in a if x.strip() != u""])

877-638-7848

Upvotes: 1

Daniel Roseman
Daniel Roseman

Reputation: 599560

Your problem is not the u. If you want to format your results in a specific way, you should use the string formatting functions.

print '-'.join(a)

Upvotes: 1

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