Reputation: 3089
NSArray *arrData = [NSArray arrayWithObjects:
@"cloud,country,plant",
@"country,cloud,plant",
@"country,plant,cloud",
@"clouds,country,plant"
,@"country,clouds,plant",
nil];
From above NSArray, I want objects which having a word "cloud"
I tried below code
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(self beginswith %@ OR self contains[CD] %@)",@"cloud",@",cloud"];
NSArray *arrResult = [arrData filteredArrayUsingPredicate:predicate];
But it's giving all 5 objects in arrResult. But I need only 3 (0,1,2) objects.
Upvotes: 1
Views: 523
Reputation: 53
This one do the trick.But i don't know whether it is the efficient way of doing this.
NSArray *arrData = [NSArray arrayWithObjects:
@"cloud,country,plant",
@"country,cloud,plant",
@"country,plant,cloud",
@"clouds,country,plant"
,@"country,clouds,plant",
nil];
NSMutableArray *resArray = [[NSMutableArray alloc]init];
for(NSString *tempString in arrData)
{
NSArray *cache = [tempString componentsSeparatedByString:@","];
if([cache containsObject:@"cloud"])
{
[resArray addObject:tempString];
}
}
Upvotes: 0
Reputation: 21808
Try:
NSPredicate* predicate = [NSPredicate predicateWithBlock:^(NSString* string, NSDictionary* options){
NSArray* array = [string componentsSeparatedByString:@","];
return [array containsObject:@"cloud"];
}];
Upvotes: 2
Reputation: 4941
Try below code,
It will work,
NSPredicate *hsPredicate = [NSPredicate predicateWithBlock:^BOOL(id _Nonnull evaluatedObject, NSDictionary<NSString *,id> * _Nullable bindings) {
NSArray *sepretArray =[((NSString*)evaluatedObject) componentsSeparatedByString:@","];
NSPredicate *subPredicate = [NSPredicate predicateWithFormat:@"self == %@",@"cloud"];
return ([sepretArray filteredArrayUsingPredicate:subPredicate].count > 0);
}];
NSArray *arrResult = [arrData filteredArrayUsingPredicate:hsPredicate];
Upvotes: 1