CODEWITHSUNDEEP
batch-file
manhyp
manhyp

Reputation: 15

How to copy the latest file based on time using batch script

I am trying to copy the newest file based on the time, I tried the below script, but it is copying all the files not the latest file:

 FOR /F %%I IN ('DIR "%FILE1%\CC*.txt" /B /O:-D /s') DO COPY %%I C:\Hyp\New\

For ex.:

xyz1.txt -- 4:23
xyz2.txt -- 4:25
xyz3.txt -- 4:30

But I need to copy only the latest file i.e. 4:30, kindly assist (not all the files).

Upvotes: 1

Views: 604

Answers (1)

aschipfl
aschipfl

Reputation: 34899

You are quite close. Instead of copying inside the bode of the FOR loop, store the file in a variable (say LATEST), which will be overwritten every iteration. After the loop has finished, the newest file is stored in the variable, supposing you define the sort order like /O:D (oldest file listed first).

This is the fixed script:

FOR /F %%I IN ('DIR "%FILE1%\CC*.txt" /B /A:-D /T:W /O:D /S') DO SET "LATEST=%%~I"
COPY "%LATEST%" "C:\Hyp\New\"

I added the filter /A:-D in order to enumerate files only (no directories).
Furthermore, I added the /T option which allows to choose which file date to use: state W for last modification (default), C for creation, or A for last access.

Upvotes: 1

Related Questions