CODEWITHSUNDEEP
javaarraysarraylistslice
robman
robman

Reputation: 73

Java - Slice any array at steps

In python we are able to do the following: 

 array = [0,1,2,3,4,5,6,7,8,9,10]
 new_array= array[::3]
 print(new_array)
>>>[0,3,6,9]

Is there an equivalent to this in Java? I have been looking for this type of array slicing, but I have had no luck. Any help would be great, Thanks!

Upvotes: 4

Views: 13772

Answers (4)

sai surya madhav
sai surya madhav

Reputation: 135

We can simply loop over array and collect values on every step

public static <T> List<T> sliceArray(List<T> arr,int start, int stop ,int step){
    System.out.println("slice with step initial = " + arr);
    List<T> res = new ArrayList<T>();
    for(int i=0;i<arr.size();i++){
        if(i%step==0) res.add(arr.get(i));
    }
    return res;
}

Upvotes: 0

Ironcache
Ironcache

Reputation: 1759

Java has no built-in mechanism for this. You could write a helper function:

public static int[] sliceArray(int[] arr, int spacing) {
    int curr = 0;
    int[] newArr = new int[((arr.length - 1) / spacing) + 1];
    for (int i = 0; i < newArr.length; ++i) {
        newArr[i] = arr[curr];
        curr += spacing;
    }
    return newArr;
}

Example

Note that Michael's answer is better (or at least less verbose) if you can utilize Java 8.

Upvotes: 0

Michael Markidis
Michael Markidis

Reputation: 4191

If you are using Java 8, then you can make use of streams and do the following:

int [] a = new int [] {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

// filter out all indices that evenly divide 3
int [] sliceArr = IntStream.range(0, a.length).filter(i -> i % 3 == 0)
    .map(i -> a[i]).toArray();

System.out.println(Arrays.toString(sliceArr));

Outputs: [0, 3, 6, 9]

Upvotes: 5

gbtimmon
gbtimmon

Reputation: 4332

There is a method in Arrays that might help. 

 int[] newArr = Arrays.copyOfRange(arr, 5,10);

It is obviously far less powerful the the python implementation.

Upvotes: 3

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