Reputation: 1892
Simple question here :
If i've got an object with initialized and uninitialized values in it. Is there an easy way to find in my db all the Entities that fit this one with hibernate ? (without listing and checking every variable of the object)
Example :
I got this class :
public class User {
private int id;
private String name;
private String email;
private boolean activ;
}
I would like to be able to do that :
User user1 = new User();
user.setActive() = true;
User user2 = new User();
user.setActive(true);
user.setName("petter")
listUser1 = findAllUser(user1);
listUser2 = findAllUser(user2);
Here listUser1 will contain all the active users and listUser2 will contain all the active user that are named petter.
Thx guys !
So my here is my code (i used a class wich is similar at the one of my example). It work just fine but the problem is that according to Eclipse : "The method createCriteria(Class) from the type SharedSessionContract is deprecated"...
public static List<Personne> findAllPersonne(Personne personne) {
List<Personne> listPersonne;
EntityManagerFactory entityManagerFactory = Persistence.createEntityManagerFactory("testhibernate0");
EntityManager entityManager = entityManagerFactory.createEntityManager();
Session session = entityManager.unwrap(Session.class);
Example personneExample = Example.create(personne);
Criteria criteria = session.createCriteria(Personne.class).add(personneExample);
listPersonne = criteria.list();
entityManager.close();
return listPersonne;
}
So .. How could i do that in a better way? I've looked into CriteriaQuery but i can't find how to use it with an example.
Upvotes: 3
Views: 15241
Reputation: 1685
In general, if an entity instance is already in your Persistence context, you can find it by primary key with EntityManager.find
. Otherwise, you can pick up a result from your database by way of JPQL or native querying.
For your particular use case, it sounds like a querying solution would be the best fit; use one of the linked query creation methods from your entity, then use the Query.getResultList()
method to pick up a list of objects that match the query criteria.
QueryByExample is also a good and valid solution, as Mr_Thorynque indicates, but as the article he linked mentions, that functionality is specific to certain JPA providers (Hibernate among them) and not JPA provider agnostic.
Upvotes: 0
Reputation: 2002
Yes it exists : the key word for google is "query by exemple" or "qbe". https://dzone.com/articles/hibernate-query-example-qbe
Upvotes: 4