Reputation: 225
First I apologize if my question seems a bit amateurish, but my knowledge with hibernate / jpa and mysql are somewhat limited.
Well, I have the following entity:
User Entity
@Entity
@Table(name = "user")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id_user")
private Long idUser;
@Column(nullable = false)
private String name;
@Column(nullable = false)
private String email;
@ManyToOne(optional = true, fetch = FetchType.EAGER)
@JoinColumn(name = "level", referencedColumnName = "id_level", nullable = true)
private Level level;
@Transient
private Long totalLikes;
}
From there, I'm trying to do the following mysql query:
public User findUserByEmail(String email) {
Session session = HibernateUtil.getSessionFactory().openSession();
User user = null;
String hql = "SELECT "
+ "u.idUser as idUser, "
+ "u.nome as nome, "
+ "u.level as level, "
+ "(SELECT count(*) FROM UserLikes likes WHERE likes.user = u.idUser) as totalLikes "
+ "FROM User u WHERE u.email = :email";
try {
Query query = session.createQuery(hql);
query.setString("email", email);
query.setResultTransformer(Transformers.aliasToBean(User.class));
user = (Usuario) query.uniqueResult();
} catch (RuntimeException ex) {
throw ex;
} finally {
session.close();
}
return user;
}
The above code returns the User normally, however returns null when the User to search in the database do not have value set in the field level. That is, if I am not wrong, hibernate does an inner join user / level and not a left join, making returns null.
Does anyone have any idea how to get around this?
Upvotes: 1
Views: 1778
Reputation: 85
i think you need use this.
@ManyToOne //simple
@JoinColumn(nullable = true) simple
and in your query using simple too.
FROM User u WHERE u.email = :email
i use this in similiar project and worked.
Good job man.
Upvotes: 4